The electric potential from an elementary electric dipole located at the origin is given by the expression $(r) = p-r/(4tE.r³) where p is the electric dipole moment vector. Show that the corresponding electric field is given by the expression E--DVф - (3 р-r-hat r-hat - p)/(4пЕг) where r-hat is the unit vector in the direction of the vector r.
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- Needs Complete typed solution with 100 % accuracy.A dielectric cylinder with absolute permittivity e, has radius b and height L. The bottom plate of the cylinder is positioned at x-y plane, concentric with the z-axis. The polarization vector in the dielectric cylinder is given P = 6Por cos(o), where Po is a constant. Find (a) Bound charge densities (b) The total charge of the cylinder. (C) Write the integral expression of the potential at P (0,0,0) explicitly. Define the integral limits and all the components in the integrant expression. Do not take the integral.Lned weu/ student/Assignment-Responses/submit?dep=27380743&tags=autosave#Q5 15.0 V 10.0 V 30.0 V 35.0 V 45.0 V D 20.0 V 25.0 V Find the work W.n in electron volts done by the electric force on a proton that moves from point A to point B. Similarly, find Wac Wan, and WAE: (Assume the proton starts and stops at rest. Enter your answers AB in ev.) HINT (a) W AB The work done by any conservative force can be related to the change in an associated potential energy: W = -APE. eV (b) WAC 25 X ev (c) WAD 45 x ev (d) WAr 45 Xev 2:17 PM P Type here to search (? 9/13/2021
- The electric field in a certain region is given by the equation E = (axn - b) i where a = 11.14 N/(Cm6), b = 9.02 N/C and n = 6 Calculate the potential difference in volts from point x1 = 0.77m to point x2 = 1.88mIn the figure below, determine the point (other than infinity) at which the electric field is zero. (Let q, = -1.65 µC and q2 = 6.90 µc.) -1.00 m-Consider the parallel-plate capacitor shown in the figure. The plate separation is 2.1 mm and the electric field inside is 15 N/C. An electron is positioned halfway between the plates and is given some initial velocity, vi. a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its speed be, in meters per second, when it reaches the positive plate in this case?
- 4) (a)Using the Gauss law find the electric field of an infinite conductor plane with charge density o. (b)Using the result in part (a) calculate the capacitance of a capacitor made of two conducting plane of 2 m2 area and with charge density o = 9.6 C/m² and these conducting planes are separated with a distance 0.1 mm and there is Aluminium oxide as the dielectric between two plates. IF NEEDED *Take gravitational constant g=10 m/s.A parallel-plate capacitor has a capacitance of 600 pF, a plate area of 240 cm², and a mica dielectric (K = 5.40) completely filling the space between the plates. At 98.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude of the free charge on the plates, and (c) the magnitude of the induced surface charge on the mica. (a) Number i (b) Number (c) Number i MO Units Units Units <The diagram below shows two point charges, A & B. The charge of A is 4.3 nC & the charge of B is -6.1 nC. Determine ΦA, ΦB, & Φnet at point P. The distance between A & P is 0.73 m & the distance between B & P is 0.02 m. (Φ is electric potential and its mks unit is V (volts). 1 V = 1 J/C.) ΦA = ΦB = Φnet =
- Each plate of an ideal air-filled parallel-plate capacitor has an area of 1,424 mm² and the separation of the plates is 0.076 mm. An electric field of 2.610 x 106 V/m is present between the plates. What is the surface charge density on the plates? (ε = 8.85 × 10-12 C²/N·m²) Give your answer in µC/m².Sketch the electric field lines of the parallel plate capacitor and the variation of the following parameters as a function of position x inside the capacitor: electric potential produced by the capacitor, potential energy of the proton, total energy of the proton, and kinetic energy of the proton.the electric field of 2 plates is E=σ/2ε0 find V (electric potential) by integrating the electric field