A parallel-plate capacitor has a capacitance of 600 pF, a plate area of 240 cm², and a mica dielectric (K = 5.40) completely filling thespace between the plates. At 98.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude ofthe free charge on the plates, and (c) the magnitude of the induced surface charge on the mica.(a) Number i(b) Number(c) NumberiMOUnitsUnitsUnits<

Part(a) The amplitude of electric field in mica. Part(b) The magnitude of the free charge on the…

Answered: A parallel-plate capacitor has a…

Similar questions

A parallel-plate capacitor has a capacitance of 570 pF, a plate area of 400 cm², and a mica dielectric (K = 5.40) completely filling the space between the plates. At 53.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude of the free charge on the plates, and (c) the magnitude of the induced surface charge on the mica. (a) Number (b) Number i M. (c) Number i jeda Units Units Units
A ring and a disk both are centered at (0, 6, 3) and are both lying on the plane y = 6. The ring has a radius of 7 m, while the disk has a radius of 9 m, so that the ring is around the disk. Determine the magnitude of the electric field in kV/m at point (0, -9, 3) if the ring has a total charge of -8 mC and the disk has a total charge of 6 mC. All coordinates are measured in meters.
Consider a polar molecule such as water, which has an electrical dipole moment of 6×10-30 Cm. Suppose we place such a molecule in an external electric field of 3.5×10-6 N/C. What is the difference in potential energy between the dipole moment being parallel to and anti-parallel to the electric field?
.A certain parallel-plate capacitor is filled with a dielectric for which k = 4.58. The area of each plate is 0.0726 m², and the plates are separated by 1.13 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 217 kN/C. What is the maximum energy that can be stored in the capacitor?
Needs Complete typed solution with 100 % accuracy.
When a battery is connected across an empty capacitor, the charge on its plates is Q0 (fig. a). If a dielectric of dielectric constant ?κ is inserted between the plates while the battery remains in place (fig. b), what is the expression for the induced charge on the dielectric surface in terms of the original plate charge Q0?
The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 3.13 × 106 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude. 15.30 + A + 2.00 cm Number i + + + 0.150 cm Units
A 5.30 cm by 2.40 cm parallel plate capacitor has the plates separated by a distance of 2.00 mm. When 4.00 × 10−11 C of charge is placed on this capacitor, what is the electric field between the plates?
The energy density in the region between the plates of a capacitor is 0.01 J/m^3. What is the magnitude of the electric fields between the plates? (E0=8.854 x 10^-12 C^2/Nm^2)