Problem 2: The electric field in a certain region is given by the equation where a = 11.44 N/(C · m³), b = 8.02 N/C, and n = 5. E = (ax" - b) i Calculate the potential difference, in volts, from point x₁ = 0.63 m to point x2 = 1.68 m, i.e., AV = V (x₂) – V (x₁). AV = | V
Problem 2: The electric field in a certain region is given by the equation where a = 11.44 N/(C · m³), b = 8.02 N/C, and n = 5. E = (ax" - b) i Calculate the potential difference, in volts, from point x₁ = 0.63 m to point x2 = 1.68 m, i.e., AV = V (x₂) – V (x₁). AV = | V
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
Transcribed Image Text:Problem 2: The electric field in a certain region is given by the equation
where a = 11.44 N/(C · m³), b = 8.02 N/C, and n = 5.
▲ Calculate the potential difference, in volts, from point x₁ = 0.63 m to point x2 = 1.68 m, i.e., AV = V (x₂ ) − V (x₁ ) .
AV =
V
cos()
asin()
tan() π ( ) 7 8 9
acos() E ^^^ 4
5 6
sinh()
1
2 3
tanh() cotanh()
E = (ax" - b) i^
sin()
cotan()
atan() acotan()
cosh()
O Degrees Radians
1
HOME
+
0
END
VO BACKSPACE DEL CLEAR
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