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Please just help with 5)
I am not sure which test I should use to prove that it diverges.
I think the comparison test is the best one to use, but if I choose 1/n as bn, an/bn doesn't give me a finite positive value in order for the test to be conclusive.
Please give me a specific answer regarding 5)
Much appriciated!
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- A home pregnancy test was given to women, then pregnancy was verified through blood tests. The following table shows the home pregnancy test results. Positive Negative Total Pregnant 58 8 66 Not Pregnant 5 79 84 Total 63 87 150 Round your answers to the nearest thousandth.`P`(positive`|`pregnant) = `P`(pregnant`|`positive) = `P`(negative`|`pregnant) = `P`(not pregnant`|`negative) =Can you help me with the code for how to do this in R please? 1. The study "Digital Footprints" ([Pew Internet and American Life Project]("Digital Footprints" (Pew Internet and American Life Project)) reported that 47\% of Internet users have searched for information about themselves online. The 47\% figure was based on a random sample of Internet users. Suppose that the sample size was `n = 400`. i) Use this information to estimate the true proportion of Internet users who searched information about themselves using a default 95\% confidence interval. ii) Repeat (i) but instead use a 98\% Confidence Level. Use function `prop.test()`. iii) What is the main difference between the intervals computed in (i) and (ii)? What do you think is the role of the confidence level in determining the precision of the confidence interval estimate?please send complete handwritten solution for Q 1 I attached sample please do like sample questions
- I am having problems on understanidng where to start with my homework. i know i am supposed to stat with seperating the left side of the eqution but i am not sure if i did it correctly. Could you please look over my work and see if i did the problem correctly?. I have attached the question and my work.The standard error of the mean is the standard deviation of the sampling distribution of the sample means (1) The standard deviation of the sampling distribution of the mean is always smaller than the standard deviation of the population under study unless n-1 and then they're equal () For a sampling distribution of the means, 90% of the means would be between 1.96 standard deviations Multiple Choice O (0) and are correct statements but not to (1) and (0) are correct statements but not ( 0,00 and are all correct statements (and (i) are correct statements but itA sample of 20 observations is taken from the normal distribution where the sample mean is 3. The normal distribution has a mean of 0 and a variance of e^beta. a)Find the estimator for the method of moments for beta and the numerical value of it?
- Based on Information from a previous study, r, = 39 people out of a random sample of n, 98 adult Americans who did not attend college belleve in extraterrestrials. However, out of a random sample of n, = 98 adult Americans who did attend college, r, = 46 clatm that they believe in extraterrestrials. Does this Indicate that the proportion of people who attended college and who beleve in extraterrestrials is higher than the proportion who did not attend college? Use a = 0.01. (a) what is the level of ugnificance? state the null and alternate hypotheses. O H, P, = Pzi H P, P2 (b) what sampling distribution will you use? what assumptions are you making? O The standard normal. The number of trials is sufficiently large. O The Student's t. We assume the population distributions are approximately normal. O The Student's t. The number of trials is sufficiently large. O The standard normal. We assume the population distributions are approxlmately normal. What is the value of the sample test…We wish to test the hypothesis that data is being generated by the binomial process Given the datum value 280, we accept that it is generated by the process if it is in a 85 % symmetric about the mean interval for the process. Using a normal approximation, we accept the hypothesis if the datum is at least L and at most U– Since 280 Select an answer in the interval. we Select an answer the hypothesis.estnavclient.psonsvc.net/#/question/1429fac6-f27b-4c12-86d0-e9ffb3f15887/d5138119-f806-4fd4-bd04-cbe9aa7c6acc Review - A Bookmark Paiz Guevar S Math 1 Unit 3 Test 2020 / 3 of 11 II Paus If B is the midpoint of AC, with point A at (5, 2) and point C at (9, 0), what is the equation of the line perpendicular to AC that passes through B? O A. y=-½x- 13 O B. y= 2x– 13 O C. y=-½ x + 5 O D. y = 2x + 5 čms US
- I received feedback from my teacher for this Intro to probability and staatistics homework problem. He said please check your work. I don't know what I did wrong. Hypergeometric geometric Suppose (22 Jolly ranchers total) and 5 out of which are blue, Now random Jolly ranchers divide evenly into two segments So, (n = 22/2 = 11) P(one obtains all 5 blue Jolly ranchers) = ? Now, K = 5 r = 5 N = 22 n = 11(divided 22 Jolly ranchers evenly into two segments ) P(X = 5) = 5C5 x 17C2 / 22C11 P(X = 5) = 0.00019278 rounded to 0.0002critical value and p value are wrong. please fix that!!In this problem, assume that the distribution of differences is approximately normal. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value by a small amount and therefore produce a slightly more "conservative" answer. At five weather stations on Trail Ridge Road in Rocky Mountain National Park, the peak wind gusts (in miles per hour) for January and April are recorded below. Weather Station 1 4 120 126 64 78 January April 139 104 111 100 88 61 Does this information indicate that the peak wind gusts are higher in January than in April? Use a = 0.01. (Let d = January- April.) (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? O Ho: Hg> 0; H,: Hj= = 0; right-tailed O Ho: Hg = 0; H,:0; left-tailed O Ho: H = 0; H,:H# 0; two-tailed O Ho: Hg = 0; H, > 0; right-tailed (b) What sampling…
