I am having problems on understanidng where to start with my homework. i know i am supposed to stat with seperating the left side of the eqution but i am not sure if i did it correctly. Could you please look over my work and see if i did the problem correctly?. I have attached the question and my work. Consider the following equation.E, k2k-1 = (n – 1)2" +1k=1(Canvas renders the summation using subscripts and superscripts ratherthan writing k=1 below the summation sign and n above the summationsign.)Let predicate P(n) be true if that equation is true for n.(a) Show that P(1) and P(2) are true. If you cannot do that, make sure thatyou understand what the equation says.(b) Using Peano Induction, prove that P(n) is true for every positive integern. (a) P(1) is true because 1 = (1-1)(2^1)+1%3D(b) Prove P(n) is for every positive integer n.E, k2k-1(п — 1)2" + 1k=1E, k- 2k-1(т — 1) 2" + 1-k=1(т + 1)2" + 1 + (m - 1) 2"(т — 1) 2" + (т + 1) 2" + 1m-21+m m + 1P(1) is true P(m) ·P(m+1)-->

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Answered: Consider the following equation. k2k-1…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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I am having problems on understanidng where to start with my homework.

i know i am supposed to stat with seperating the left side of the eqution but i am not sure if i did it correctly. Could you please look over my work and see if i did the problem correctly?. I have attached the question and my work.

Consider the following equation.
E, k2k-1 = (n – 1)2" +1
k=1
(Canvas renders the summation using subscripts and superscripts rather
than writing k=1 below the summation sign and n above the summation
sign.)
Let predicate P(n) be true if that equation is true for n.
(a) Show that P(1) and P(2) are true. If you cannot do that, make sure that
you understand what the equation says.
(b) Using Peano Induction, prove that P(n) is true for every positive integer
n.

(a) P(1) is true because 1 = (1-1)(2^1)+1
%3D
(b) Prove P(n) is for every positive integer n.
E, k2k-1
(п — 1)2" + 1
k=1
E, k- 2k-1
(т — 1) 2" + 1
-
k=1
(т + 1)2" + 1 + (m - 1) 2"
(т — 1) 2" + (т + 1) 2" + 1
m
-
21+m m + 1
P(1) is true P(m) ·
P(m+1)
-->

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