I received feedback from my teacher for this Intro to probability and staatistics homework problem. He said please check your work. I don't know what I did wrong.   Hypergeometric geometric  Suppose (22 Jolly ranchers total) and 5 out of which are blue, Now random Jolly ranchers divide evenly into two segments So, (n = 22/2 = 11)   P(one obtains all 5 blue Jolly ranchers) = ? Now, K = 5 r = 5  N = 22 n = 11(divided 22 Jolly ranchers evenly into two segments ) P(X = 5) = 5C5 x 17C2 / 22C11 P(X = 5) = 0.00019278 rounded to 0.0002

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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I received feedback from my teacher for this Intro to probability and staatistics homework problem. He said please check your work. I don't know what I did wrong.

 

Hypergeometric geometric 

Suppose (22 Jolly ranchers total) and 5 out of which are blue,

Now random Jolly ranchers divide evenly into two segments

So, (n = 22/2 = 11)

 

P(one obtains all 5 blue Jolly ranchers) = ?

Now,

K = 5

r = 5 

N = 22

n = 11(divided 22 Jolly ranchers evenly into two segments )

P(X = 5) = 5C5 x 17C2 / 22C11

P(X = 5) = 0.00019278 rounded to 0.0002

Expert Solution
Step 1

Given that,

There are 22 jolly ranches and of which 5 are blue.

Randomly jolly ranchers are divided evenly into two segments.

N=22n=11K=5r=5

The pmf hypergeometric distribution is as follows.

P(X=r)=CrK ×Cn-rN-KCnN

N is population size

K is the number of successes in the population

n is the sample size

r is the number of successes in the sample

The combination is as follows.

Cxn=n!(n-x)!×x!

The factorial is as follows,

n!=n×(n-1)×...×1

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