Please explain the formula (process) used to get the Red undelived numbers, Thanks!! example each Row, please. ISI 1/IS1

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
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### Enzyme Kinetics with Inhibitors

#### Data Analysis from Kinetics Experiments

The following kinetic data was obtained for an enzyme with substrate concentration \([S]\) and velocity \(v\) under different conditions:

- **No inhibitor (Condition 1)**
- **Inhibitor 2 present (Condition 2)**
- **Inhibitor 3 present (Condition 3)**

Assume enzyme concentration \([E]\) is constant across experiments.

#### Table of Kinetic Data

| [S] (mM) | \(v\) (1) \((\mu \text{mol/mL/sec})\) | \(v\) (2) \((\mu \text{mol/mL/sec})\) | \(v\) (3) \((\mu \text{mol/mL/sec})\) |
|----------|----------------------------------------|-----------------------------------------|-----------------------------------------|
| 1        | 12                                     | 4.3                                     | 5.5                                     |
| 2        | 20                                     | 8                                       | 9                                       |
| 4        | 29                                     | 14                                      | 13                                      |
| 8        | 35                                     | 21                                      | 16                                      |
| 12       | 40                                     | 26                                      | 18                                      |

#### Double-Reciprocal (Lineweaver-Burk) Plot Data

| [S] (mM) | \(1/[S]\) (M\(^{-1}\)) | \(1/v\) (1) (mL/sec/μmol) | \(1/v\) (2) (mL/sec/μmol) | \(1/v\) (3) (mL/sec/μmol) |
|----------|------------------------|--------------------------|--------------------------|--------------------------|
| 1        | 1000                   | 8.33 x \(10^{4}\)        | 2.33 x \(10^{5}\)        | 1.82 x \(10^{5}\)        |
| 2        | 500                    | 5.00 x \(10^{4}\)        | 1.25 x \(10^{5}\)        | 1.11 x \(10^{5}\)        |
| 4        | 250                    | 3.45 x \(
Transcribed Image Text:### Enzyme Kinetics with Inhibitors #### Data Analysis from Kinetics Experiments The following kinetic data was obtained for an enzyme with substrate concentration \([S]\) and velocity \(v\) under different conditions: - **No inhibitor (Condition 1)** - **Inhibitor 2 present (Condition 2)** - **Inhibitor 3 present (Condition 3)** Assume enzyme concentration \([E]\) is constant across experiments. #### Table of Kinetic Data | [S] (mM) | \(v\) (1) \((\mu \text{mol/mL/sec})\) | \(v\) (2) \((\mu \text{mol/mL/sec})\) | \(v\) (3) \((\mu \text{mol/mL/sec})\) | |----------|----------------------------------------|-----------------------------------------|-----------------------------------------| | 1 | 12 | 4.3 | 5.5 | | 2 | 20 | 8 | 9 | | 4 | 29 | 14 | 13 | | 8 | 35 | 21 | 16 | | 12 | 40 | 26 | 18 | #### Double-Reciprocal (Lineweaver-Burk) Plot Data | [S] (mM) | \(1/[S]\) (M\(^{-1}\)) | \(1/v\) (1) (mL/sec/μmol) | \(1/v\) (2) (mL/sec/μmol) | \(1/v\) (3) (mL/sec/μmol) | |----------|------------------------|--------------------------|--------------------------|--------------------------| | 1 | 1000 | 8.33 x \(10^{4}\) | 2.33 x \(10^{5}\) | 1.82 x \(10^{5}\) | | 2 | 500 | 5.00 x \(10^{4}\) | 1.25 x \(10^{5}\) | 1.11 x \(10^{5}\) | | 4 | 250 | 3.45 x \(
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