Please explain the formula (process) used to get the Red undelived numbers, Thanks!! example each Row, please. ISI 1/IS1
Please explain the formula (process) used to get the Red undelived numbers, Thanks!! example each Row, please. ISI 1/IS1
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
![### Enzyme Kinetics with Inhibitors
#### Data Analysis from Kinetics Experiments
The following kinetic data was obtained for an enzyme with substrate concentration \([S]\) and velocity \(v\) under different conditions:
- **No inhibitor (Condition 1)**
- **Inhibitor 2 present (Condition 2)**
- **Inhibitor 3 present (Condition 3)**
Assume enzyme concentration \([E]\) is constant across experiments.
#### Table of Kinetic Data
| [S] (mM) | \(v\) (1) \((\mu \text{mol/mL/sec})\) | \(v\) (2) \((\mu \text{mol/mL/sec})\) | \(v\) (3) \((\mu \text{mol/mL/sec})\) |
|----------|----------------------------------------|-----------------------------------------|-----------------------------------------|
| 1 | 12 | 4.3 | 5.5 |
| 2 | 20 | 8 | 9 |
| 4 | 29 | 14 | 13 |
| 8 | 35 | 21 | 16 |
| 12 | 40 | 26 | 18 |
#### Double-Reciprocal (Lineweaver-Burk) Plot Data
| [S] (mM) | \(1/[S]\) (M\(^{-1}\)) | \(1/v\) (1) (mL/sec/μmol) | \(1/v\) (2) (mL/sec/μmol) | \(1/v\) (3) (mL/sec/μmol) |
|----------|------------------------|--------------------------|--------------------------|--------------------------|
| 1 | 1000 | 8.33 x \(10^{4}\) | 2.33 x \(10^{5}\) | 1.82 x \(10^{5}\) |
| 2 | 500 | 5.00 x \(10^{4}\) | 1.25 x \(10^{5}\) | 1.11 x \(10^{5}\) |
| 4 | 250 | 3.45 x \(](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeadb183-1175-48ee-be1d-be4cbd36e1e9%2F86ad7030-65d9-4ae5-b1bd-bdf2f636c249%2Fs64aaso_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Enzyme Kinetics with Inhibitors
#### Data Analysis from Kinetics Experiments
The following kinetic data was obtained for an enzyme with substrate concentration \([S]\) and velocity \(v\) under different conditions:
- **No inhibitor (Condition 1)**
- **Inhibitor 2 present (Condition 2)**
- **Inhibitor 3 present (Condition 3)**
Assume enzyme concentration \([E]\) is constant across experiments.
#### Table of Kinetic Data
| [S] (mM) | \(v\) (1) \((\mu \text{mol/mL/sec})\) | \(v\) (2) \((\mu \text{mol/mL/sec})\) | \(v\) (3) \((\mu \text{mol/mL/sec})\) |
|----------|----------------------------------------|-----------------------------------------|-----------------------------------------|
| 1 | 12 | 4.3 | 5.5 |
| 2 | 20 | 8 | 9 |
| 4 | 29 | 14 | 13 |
| 8 | 35 | 21 | 16 |
| 12 | 40 | 26 | 18 |
#### Double-Reciprocal (Lineweaver-Burk) Plot Data
| [S] (mM) | \(1/[S]\) (M\(^{-1}\)) | \(1/v\) (1) (mL/sec/μmol) | \(1/v\) (2) (mL/sec/μmol) | \(1/v\) (3) (mL/sec/μmol) |
|----------|------------------------|--------------------------|--------------------------|--------------------------|
| 1 | 1000 | 8.33 x \(10^{4}\) | 2.33 x \(10^{5}\) | 1.82 x \(10^{5}\) |
| 2 | 500 | 5.00 x \(10^{4}\) | 1.25 x \(10^{5}\) | 1.11 x \(10^{5}\) |
| 4 | 250 | 3.45 x \(
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