Please answer the following question(s): 1. f = 7.5 N a = 0 = 12.5 Free-body diagram F₁ F2 m/s² degrees F₁ F₂ F₁: 45° 30° Two children pull a third child on a snow saucer sled exerting forces F₁ and F₂ as shown above in the figure. Find the acceleration a and direction of the 46-kg sled and child system. Note that the direction of the frictional force f is unspecified; it will be in the opposite direction of the sum of F₁ and F2 Think and Prepare 1. Friction acts opposite the intended motion of snow saucer. 2. Given F₁ and F2, what direction will the saucer move if initially at rest? In the direction of F₁? In the direction of F₂? Or in the direction of the resultant of F₁ and F₂? = 10 N 3. In what direction will friction act? Opposite F₁? Opposite F₂? Or opposite the resultant of F, and F₂? Enter to 2 significant figures F₂ = 8 N

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# Physics Problem: Forces on a Snow Saucer Sled

### Problem Description
Two children pull a third child on a snow saucer sled exerting forces \( F_1 \) and \( F_2 \) as depicted in the figure. You need to find the acceleration \( a \) and direction \( \theta \) of the 46-kg sled and child system. Keep in mind that the direction of the frictional force \( f \) is not specified; it will be in the opposite direction of the resultant force of \( F_1 \) and \( F_2 \).

### Diagram Explanation
- **Forces:**
  - \( F_1 = 10 \, \text{N} \) applied at an angle of 45°.
  - \( F_2 = 8 \, \text{N} \) applied at an angle of 30°.
- **Free-Body Diagram:**
  - Displays vectors \( F_1 \), \( F_2 \), and \( f = 7.5 \, \text{N} \) acting in opposing directions.
  - Friction \( f \) acts in a direction opposite to the intended motion of the sled, represented by a dashed arrow.

### Think and Prepare
1. **Friction**: Acts opposite to the intended direction of motion of the snow saucer.
2. **Direction of Motion**: Determine if the saucer moves initially towards \( F_1 \), \( F_2 \), or the resultant of both forces.
3. **Direction of Friction**: Determine if friction opposes \( F_1 \), \( F_2 \), or the resultant of \( F_1 \) and \( F_2 \).

### Calculated Values
- **Acceleration \( a \)**: \( 0.7 \, \text{m/s}^2 \)
- **Direction \( \theta \)**: \( 12.5 \, \text{degrees} \)

Enter these values to two significant figures.
Transcribed Image Text:# Physics Problem: Forces on a Snow Saucer Sled ### Problem Description Two children pull a third child on a snow saucer sled exerting forces \( F_1 \) and \( F_2 \) as depicted in the figure. You need to find the acceleration \( a \) and direction \( \theta \) of the 46-kg sled and child system. Keep in mind that the direction of the frictional force \( f \) is not specified; it will be in the opposite direction of the resultant force of \( F_1 \) and \( F_2 \). ### Diagram Explanation - **Forces:** - \( F_1 = 10 \, \text{N} \) applied at an angle of 45°. - \( F_2 = 8 \, \text{N} \) applied at an angle of 30°. - **Free-Body Diagram:** - Displays vectors \( F_1 \), \( F_2 \), and \( f = 7.5 \, \text{N} \) acting in opposing directions. - Friction \( f \) acts in a direction opposite to the intended motion of the sled, represented by a dashed arrow. ### Think and Prepare 1. **Friction**: Acts opposite to the intended direction of motion of the snow saucer. 2. **Direction of Motion**: Determine if the saucer moves initially towards \( F_1 \), \( F_2 \), or the resultant of both forces. 3. **Direction of Friction**: Determine if friction opposes \( F_1 \), \( F_2 \), or the resultant of \( F_1 \) and \( F_2 \). ### Calculated Values - **Acceleration \( a \)**: \( 0.7 \, \text{m/s}^2 \) - **Direction \( \theta \)**: \( 12.5 \, \text{degrees} \) Enter these values to two significant figures.
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