Kindly provide the solution to the following question using the GRASS method. Free Body Diagrams and Problem Solving (Dynamics Unit): Determine the acceleration of a 55 kg sled coming down a snow hill at 30 degrees to the horizontal ground if the coefficient of friction between the sled and the snow hill is 0.14. Image attached is a guide on how to use the GRASS method on a question and the other image are the formulas. tiver:Ad AdRequired:Ad Ad AdYAnclysis:Let mooth & west be positive tv4d² = Ad + Ad2Sektion:N(20.0km) (sin 25°)(20.0xmXcos 25°)(45.0 kyksin 40) XWE(45.0km) (cos 40.00)40.0⁰Ad Ad + AdBd² = (-20.0kn) (co₁ 250) + (45.0 kn)(sin 40.0°)bota= 10.799 kmAd = A + ActAdy = (20.0 km.) (sin 250) + (45.0 kn X(cos 40.0")Ady = [42.924 km]| AZ²₂1 = √(40₂)² + (Ad4₂) ²142, 1 =√ √/(10.799 kn)² + (42.924 kn)²1Ad1=44.262 kmScheton (contid):-O + tan" (Ads)ở bán 42.921 km-110.799 Kn0 = 75.9°Statene tiThen fore, the displacement ofthe whole is 4.43 x 10¹ kn [W76″N MotionAd = Ad₁ + Ad₂ + ...bsin Basin AV₂ VtVAB = VAC + VCBa av==ForcesācF = ma=Csin Cc²=a² + b² sindtāav ( t)²2F = mã,Uniform Circular Motion1²F = may=-d = v₁ t+VXY =√xxā =v=x =FmF₂Unit 1 Dynamics=àtHcos-b+√b²-4ac2aF = mgGMmā=à = (v₁ + √₂) t2HV7.ttan 0 =1.AA==bhv² = ₁² +2αavF₁ = FNv=2-rV=Tc²=a² + b² - 2ab cos 0Y₂ Y₁X₂ X₁āav( t)²2āFA = lws,maxNSlope=d=v₂ ta = 4 ² rf² Tr=}V=FNGMr

Name: Kindly provide the solution to the following question using the GRASS
Uploaded: 2024-03-20T06:57:57.000Z
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Description: Kindly provide the solution to the following question using the GRASS method. Free Body Diagrams and Problem Solving (Dynamics Unit): Determine the acceleration of a 55 kg sled coming down a snow hill at 30 degrees to the horizontal ground if the co