IV. Applying Wnet ext = AK %3D Two carts, C and D, are initially at rest on a horizontal frictionless table as shown in the top-view diagram below. A constant force of magnitude F, is exerted on each cart as it travels between two marks on the table. Cart D has a greater mass than cart C. Top view F, Frictionless table < mp mc F D Second mark First mark A. Do you agree or disagree with the statement below regarding the final kinetic energy of each cart? Explain. "Since the same force is exerted on both carts, the cart with the smaller mass will move quickly, while the cart with the larger mass will move slowly. Since the velocity is squared to get the kinetic energy but mass isn't, the cart with the bigger speed must have more kinetic energy." dig ow or
IV. Applying Wnet ext = AK %3D Two carts, C and D, are initially at rest on a horizontal frictionless table as shown in the top-view diagram below. A constant force of magnitude F, is exerted on each cart as it travels between two marks on the table. Cart D has a greater mass than cart C. Top view F, Frictionless table < mp mc F D Second mark First mark A. Do you agree or disagree with the statement below regarding the final kinetic energy of each cart? Explain. "Since the same force is exerted on both carts, the cart with the smaller mass will move quickly, while the cart with the larger mass will move slowly. Since the velocity is squared to get the kinetic energy but mass isn't, the cart with the bigger speed must have more kinetic energy." dig ow or
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Could you help with section IV and A?
![**Work and changes in kinetic energy**
**III. Relating Work and Changes in Kinetic Energy for Particle-like Systems**
A. Use the definition of kinetic energy to determine the sign of the change in kinetic energy, \( \Delta K \), for an object that is (1) speeding up, (2) slowing down, or (3) moving at constant speed.
B. Use your results thus far to complete the table at right.
| | Part I.B Stage 1 | Part I.B Stage 2 | Part II Block A | Part II Block B |
|----------------------|------------------|------------------|----------------|----------------|
| Sign of \( \Delta K \) | | | | |
| Sign of \( W_{net} \) | | | | |
The net work done on a system by external forces causes a change in the total energy of that system. In parts I and II, the only form of energy being changed is the kinetic energy, so
\[ W_{net}^{ext} = \Delta K \]
C. Check that your results in the table above are consistent with the expression \( W_{net}^{ext} = \Delta K \).
**IV. Applying \( W_{net}^{ext} = \Delta K \)**
Two carts, C and D, are initially at rest on a horizontal frictionless table as shown in the top-view diagram below. A constant force of magnitude \( F_0 \) is exerted on each cart as it travels between two marks on the table. Cart D has a greater mass than Cart C.
*Diagram Description:*
- The diagram is a top view of a frictionless table.
- Two carts, labeled C (mass \(m_C\)) and D (mass \(m_D\)), where \(m_C < m_D\), are illustrated.
- \(F_0\) (a constant force) is applied to both carts.
- The carts travel in the direction of the applied force, from a first mark to a second mark.
*Statement for analysis:*
"Since the same force is exerted on both carts, the cart with the smaller mass will move quickly, while the cart with the larger mass will move slowly. Since the velocity is squared to get the kinetic energy but mass isn’t, the cart with the bigger speed must have more kinetic energy."
A. Do you agree or disagree with the statement below](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc33b68d8-ffa3-4dac-adf6-5bab0282a81a%2Fa1f555a9-3af1-4090-890a-366d9298ebd6%2F8ji257f_reoriented.jpeg&w=3840&q=75)
Transcribed Image Text:**Work and changes in kinetic energy**
**III. Relating Work and Changes in Kinetic Energy for Particle-like Systems**
A. Use the definition of kinetic energy to determine the sign of the change in kinetic energy, \( \Delta K \), for an object that is (1) speeding up, (2) slowing down, or (3) moving at constant speed.
B. Use your results thus far to complete the table at right.
| | Part I.B Stage 1 | Part I.B Stage 2 | Part II Block A | Part II Block B |
|----------------------|------------------|------------------|----------------|----------------|
| Sign of \( \Delta K \) | | | | |
| Sign of \( W_{net} \) | | | | |
The net work done on a system by external forces causes a change in the total energy of that system. In parts I and II, the only form of energy being changed is the kinetic energy, so
\[ W_{net}^{ext} = \Delta K \]
C. Check that your results in the table above are consistent with the expression \( W_{net}^{ext} = \Delta K \).
**IV. Applying \( W_{net}^{ext} = \Delta K \)**
Two carts, C and D, are initially at rest on a horizontal frictionless table as shown in the top-view diagram below. A constant force of magnitude \( F_0 \) is exerted on each cart as it travels between two marks on the table. Cart D has a greater mass than Cart C.
*Diagram Description:*
- The diagram is a top view of a frictionless table.
- Two carts, labeled C (mass \(m_C\)) and D (mass \(m_D\)), where \(m_C < m_D\), are illustrated.
- \(F_0\) (a constant force) is applied to both carts.
- The carts travel in the direction of the applied force, from a first mark to a second mark.
*Statement for analysis:*
"Since the same force is exerted on both carts, the cart with the smaller mass will move quickly, while the cart with the larger mass will move slowly. Since the velocity is squared to get the kinetic energy but mass isn’t, the cart with the bigger speed must have more kinetic energy."
A. Do you agree or disagree with the statement below
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