In the figure the capacitances are C₁ = 0.78 µF and C₂ = 2.8 μF, and both capacitors are charged to a potential difference of V = 120 V but with opposite polarity as shown. Switches S₁ and S2 are now closed. (a) What is now the potential difference between points a and b? What now is the charge on capacitor (b) 1 and (c) 2? (a) Number i (b) Number (c) Number i Units Units Units C₁ Cq TE

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In the figure the capacitances are C₁ = 0.78 µF and C₂ = 2.8 μF, and both capacitors are charged to a potential difference of V = 120 V
but with opposite polarity as shown. Switches S₁ and S2 are now closed. (a) What is now the potential difference between points a and
b? What now is the charge on capacitor (b) 1 and (c) 2?
(a) Number i
(b) Number i
(c) Number
i
Units
Units
Units
C₁
Cq
TE
Transcribed Image Text:In the figure the capacitances are C₁ = 0.78 µF and C₂ = 2.8 μF, and both capacitors are charged to a potential difference of V = 120 V but with opposite polarity as shown. Switches S₁ and S2 are now closed. (a) What is now the potential difference between points a and b? What now is the charge on capacitor (b) 1 and (c) 2? (a) Number i (b) Number i (c) Number i Units Units Units C₁ Cq TE
Expert Solution
Step 1: Given data and concept used

C1= 0.78 muF

C= 2.8 muF

Both are charged to a potential of 120V

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