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Please answer question #7

Please answer question #7

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer question #7

Data Table mass unknown sample (g) volume HCl (mL) molarity HCl (mol/L) 0.5007 25.00 12.1 3. Write a balanced chemical equation for the reaction between NaHCO3 and HCl. NaHCO: (s) + HCI(ag) → H2CO; (ag) + NaCl (ag) 4. Calculate the moles of HC by multiplying the volume of HCl in liters and the molarity of HCl in mol/L. (Keep four significant digits in all of the calculations.) 0.3025 moles 5. The moles of HCl can be converted to moles of NaHCO; using the coefficients from the balanced equation. What is the mole to mole ratio of HCl to NaHCO3? How many moles of NaHCO3 are present in the sample? HCl and NaHCO2 molar ratio 1:1. amount of unknown sample = 0.5007 g Molar mass of NaHCO; = 84.007 g/mol Moles of NaHCO, are present in the sample = 0.5007 g/84.007 g/mol = 0.00596 mol 6. Calculate the grams of NaHCO; by multiplying the moles of NaHCO3 by the molecular weight of NaHCO3 (84.007 g/mol). 0.5007 g 7. The mass % of NaHCO3 present in the sample can be calculated by dividing the mass of NaHCO; from question #6 by the mass of the sample from the data table and multiplying by 100. What is the mass % of NaHCO;?
Transcribed Image Text:Data Table mass unknown sample (g) volume HCl (mL) molarity HCl (mol/L) 0.5007 25.00 12.1 3. Write a balanced chemical equation for the reaction between NaHCO3 and HCl. NaHCO: (s) + HCI(ag) → H2CO; (ag) + NaCl (ag) 4. Calculate the moles of HC by multiplying the volume of HCl in liters and the molarity of HCl in mol/L. (Keep four significant digits in all of the calculations.) 0.3025 moles 5. The moles of HCl can be converted to moles of NaHCO; using the coefficients from the balanced equation. What is the mole to mole ratio of HCl to NaHCO3? How many moles of NaHCO3 are present in the sample? HCl and NaHCO2 molar ratio 1:1. amount of unknown sample = 0.5007 g Molar mass of NaHCO; = 84.007 g/mol Moles of NaHCO, are present in the sample = 0.5007 g/84.007 g/mol = 0.00596 mol 6. Calculate the grams of NaHCO; by multiplying the moles of NaHCO3 by the molecular weight of NaHCO3 (84.007 g/mol). 0.5007 g 7. The mass % of NaHCO3 present in the sample can be calculated by dividing the mass of NaHCO; from question #6 by the mass of the sample from the data table and multiplying by 100. What is the mass % of NaHCO;?
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