Please answer question #7 Data Tablemass unknown sample (g)volume HCl (mL)molarity HCl (mol/L)0.500725.0012.13. Write a balanced chemical equation for the reaction between NaHCO3 and HCl.NaHCO: (s) + HCI(ag) → H2CO; (ag) + NaCl (ag)4. Calculate the moles of HC by multiplying the volume of HCl in liters and the molarity of HCl inmol/L. (Keep four significant digits in all of the calculations.) 0.3025 moles5. The moles of HCl can be converted to moles of NaHCO; using the coefficients from the balancedequation. What is the mole to mole ratio of HCl to NaHCO3? How many moles of NaHCO3 arepresent in the sample?HCl and NaHCO2 molar ratio 1:1.amount of unknown sample = 0.5007 gMolar mass of NaHCO; = 84.007 g/molMoles of NaHCO, are present in the sample = 0.5007 g/84.007 g/mol= 0.00596 mol6. Calculate the grams of NaHCO; by multiplying the moles of NaHCO3 by the molecular weight ofNaHCO3 (84.007 g/mol).0.5007 g7. The mass % of NaHCO3 present in the sample can be calculated by dividing the mass of NaHCO; fromquestion #6 by the mass of the sample from the data table and multiplying by 100.What is the mass % of NaHCO;?

Answered: Please answer question #7

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Chemistry

Please answer question #7

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

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Please answer question #7

Data Table
mass unknown sample (g)
volume HCl (mL)
molarity HCl (mol/L)
0.5007
25.00
12.1
3. Write a balanced chemical equation for the reaction between NaHCO3 and HCl.
NaHCO: (s) + HCI(ag) → H2CO; (ag) + NaCl (ag)
4. Calculate the moles of HC by multiplying the volume of HCl in liters and the molarity of HCl in
mol/L. (Keep four significant digits in all of the calculations.) 0.3025 moles
5. The moles of HCl can be converted to moles of NaHCO; using the coefficients from the balanced
equation. What is the mole to mole ratio of HCl to NaHCO3? How many moles of NaHCO3 are
present in the sample?
HCl and NaHCO2 molar ratio 1:1.
amount of unknown sample = 0.5007 g
Molar mass of NaHCO; = 84.007 g/mol
Moles of NaHCO, are present in the sample = 0.5007 g/84.007 g/mol
= 0.00596 mol
6. Calculate the grams of NaHCO; by multiplying the moles of NaHCO3 by the molecular weight of
NaHCO3 (84.007 g/mol).
0.5007 g
7. The mass % of NaHCO3 present in the sample can be calculated by dividing the mass of NaHCO; from
question #6 by the mass of the sample from the data table and multiplying by 100.
What is the mass % of NaHCO;?

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