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Phosphate can be removed from drinking water supplies by treating the water with Ca(OH)2: 5Ca(OH)2(aq) +3PO4(aq) Cas(PO4)3(s)+90H¯ (aq) How much Ca(OH)2 is required to remove 90.0% of the PO43- from 6.10x106 L of drinking water containing 25.0 mg/L of PO43-? g

Phosphate can be removed from drinking water supplies by treating the water with Ca(OH)2: 5Ca(OH)2(aq) +3PO4(aq) Cas(PO4)3(s)+90H¯ (aq) How much Ca(OH)2 is required to remove 90.0% of the PO43- from 6.10x106 L of drinking water containing 25.0 mg/L of PO43-? g

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.107PAE
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Phosphate can be removed from drinking water supplies by treating the water with Ca(OH)2: 5Ca(OH)2(aq) +3PO4(aq) Cas(PO4)3(s)+90H¯ (aq) How much Ca(OH)2 is required to remove 90.0% of the PO43- from 6.10x106 L of drinking water containing 25.0 mg/L of PO43-? g
Transcribed Image Text:Phosphate can be removed from drinking water supplies by treating the water with Ca(OH)2: 5Ca(OH)2(aq) +3PO4(aq) Cas(PO4)3(s)+90H¯ (aq) How much Ca(OH)2 is required to remove 90.0% of the PO43- from 6.10x106 L of drinking water containing 25.0 mg/L of PO43-? g
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