Perform the analysis of variance (ANOVA) at the 5% significance level to identify is there any difference in the mean between
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Perform the analysis of variance (ANOVA) at the 5% significance level to
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- Assuming that the distribution of the measurements made was normal, 13 measurements were made for the melting points of copper and it was observed that the mean and variance were 169 and 81, respectively. Test whether the melting point variability of copper is different from 64 at the 1% significance level, interpret the decision you made as a result of the test. While testing the hypothesis test, apply the 4 stages and show them separately.According to a national statistics bureau, 3.7% of males living in the Southwest were retired exterminators. A researcher believes that the percentage has increased since then. She randomly selects 250 males in the Southwest and finds that 4 of them are retired exterminators. Test the researcher's claim at the level of significance=0.01. Apply p-value and classical approaches. Show step1-3.Delta studied the relationship between the number of passengers on a particular flight and the cost of the flight. It seems logical that more passengers on the flight will result in more weight & luggage, which would create higher fuel costs. For a sample of 19 flights, the correlation between the number of passengers and total fuel cost was 0.669. State the decision rule for 0.05 significance level (round to 3 decimal places) Compute the value of the test statistic (round to 2 decimal places)
- A test statistic for one of the tests in this unit is given, along with information about degrees of freedom. Give the p-value and indicate whether the results are significant at the 5% level. An analysis of variance test with F-statistic = 7.42 and df-numerator = 3 and df -denominator = 56 Round your answer to four decimal places. p-value =Twenty individual were selected at random from three small barangays in bongao, Tawi-Tawi, and ages were recoded in the table below. Perform the analysis of variance at the 0.05 level of confidence and indicate whether or not the individual in these barangays differed in mean age. Barangays 1 2 3 23 23 15 15 45 25 24 42 30 35 45 40 23 36 18 17 33 21 40 38Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 408 of the 536 randomly selected wildfires looked at in the south were caused by humans while 393 of the 579 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean t-test for the difference between two independent population means t-test for the difference between two dependent population means z-test for a population proportion z-test for the difference between two population proportions The null and alternative hypotheses would be: Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (please enter a decimal) Select an answer μ1 p1 Select an answer < > ≠ = Select an answer μ2 p2 (Please enter a decimal) The test statistic ? t z = (please show your…
- A tyre manufacturer wants to know if there is a sizable price gap between their tyres and those of a rival. The tyre company gathered cost information for 7 tyres that were randomly chosen from their own production and 7 tyres that were randomly chosen from the manufacturing of a rival. The manufacturer believes that the two groups will exhibit equal variances. Determine whether there is a significant difference in the mean price of the tyres using a 5% threshold of significance, and then interpret your findings. Table 3 Cost ($) 220 270 320 370 380 390 Opponents product cost(S) 190 230 370 370 320 320 250 340Reports show that 92% of online searches in March 2021 use Google as the search engine. A network administrator wants to determine whether the percentage of searches that use Google is different in their company. They sample 800 searches and find that 758 of them use Google. Can they conclude that the percentage of searches that use Google in this company differs from 92%? Use the a = 0.05 level of significance.account_circle Math StatisticsQ&A LibraryPolokwane Butchery supplies Vienna sausages in the entire of KZN province. An Inspector from the CCSA has been sceptical of the mass of the Vienna sausage packs after receiving numerous complaints. He wants to investigate the marked mass shown on Vienna sausages. A pilot study showed a mean of 11.8kg per pack and a variance of 0.49kg. How many packs should the Inspector sample in order to be 99% confident that the sample mean will differ by at most 0.2kg? Polokwane Butchery supplies Vienna sausages in the entire of KZN province. An Inspector from the CCSA has been sceptical of the mass of the Vienna sausage packs after receiving numerous complaints. He wants to investigate the marked mass shown on Vienna sausages. A pilot study showed a mean of 11.8kg per pack and a variance of 0.49kg. How many packs should the Inspector sample in order to be 99% confident that the sample mean will differ by at most 0.2kg?…
- A researcher believes that the mean earnings of top-paid actors, athletes and musicians are the same. The earnings (in millions of dollars) for several randomly selected people from each category are shown in the table below. It has been confirmed that the population variance for each group is equal and that earnings follow a normal distribution for top-pain actors, athletes and musicians. Use a 5% significance to test the claim. Job Actor Actor Actor Actor Actor Actor Actor Actor Actor Actor Actor Actor Actor Actor Athlete Athlete Athlete Athlete Athlete Athlete Athlete Athlete Athlete Athlete Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Musician Earnings 31 34 33 26 21 33 30 36 27 27 34 37 36 23 30 39 46 41 36 50 30 44 43 44 46 54 65 30 39 52 37 41 45 60 60 31 49 45 45 What is the factor variable? Top-Paid Job Type What is the response variable? Earnings Test Statistic: 15.2043 X P-Value: 0.0000✓ O…An ANOVA is used to evaluate the mean differences among three treatment conditions with a sample of n = 12 participants in each treatment. For this study, what is dfwithin treatment?State the two-way ANOVA identity for degrees of freedom and interpret its meaning with regard to partitioning the total degrees of freedom in the data.