TREE-DELETE(root, x):should not happen!# x.key not in S# nothing to removeif root is NIL:passelse if x.key < root.item.key:root.left <- TREE-DELETE(root.left, x)else if x.key > root.item.key:root.right <- TREE-DELETE (root.right, x)# x.keyif root.left is NIL:root <- root.rightelse if root.right is NIL:else:root.item.key so Remove root.item.==# NIL if both children missingroot <- root.leftelse:# Root has two children: remove element with smallest key in right subtree and# move it to root. Assumption: DELETE-MIN returns two values: element removed# from right subtree and root of resulting subtree (in case root.right changes).root.item, root.right <- DELETE-MIN(root.right)return rootDELETE-MIN (root):# Remove element with smallest key in root's subtree;# return element removed and root of resulting subtree.if root.left is NIL:# Root stores item with smallest key; replace with right child.return root.item, root.rightelse:# Left subtree not empty: root not the smallest.item, root.left <- DELETE-MIN(root.left)return item, root 2. BST Deletion Average Case(b) We are interested in the total number of calls to TREE-DELETE and DELETE-MIN that willbe performed to delete nodes from this tree. The code for these functions is distributed withthis test in the file bst-deletions.pdf. It is also the same code that was taught in week 3lectures.Howmanycalls would be made to these two functions (in total) if we deleted 2?(c) How many calls will be made to these functions if we deleted 5 (from the original tree thatstill holds the 2)?(d) Assume now that we will randomly select one node from the tree for deletion. Assume thatthe probability of selecting the 7 is and the probability of selecting the 8 is . The othernodes in the tree are equally likely to be selected for deletion and the probability of callingdelete on a node that is not in the tree is 0. Calculate the average-case number of total callsto TREE-DELETE and DELETE-MIN. Showyourwork.

Answer: I have given answered in the handwritten format in brief explanation.

Answered: pass # nothing to remove else if x.key…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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bool DelOddCopEven(Node* headPtr) { if (headPtr == nullptr) { return false; } Node* prev = nullptr; Node* current = headPtr; while (current != nullptr) { if (current->data % 2 != 0) { // Odd-valued node, delete it if (prev != nullptr) { prev->link = current->link; } else { headPtr = current->link; } Node* temp = current; current = current->link; delete temp; } else { // Even-valued node, create a copy and insert it after the original node Node* newNode = new Node; newNode->data = current->data; newNode->link = current->link; current->link = newNode; // Update the previous and current pointers prev = newNode; current = newNode->link; } } return true;} int FindListLength(Node* headPtr){ int length = 0;…
Fix the main file errors. public void Insert(int newItem) { Node parent = null; Node newNode = new Node(newItem); Node current = root; while (current != null) { parent = current; if (newNode.item < current.item) { current = current.Left; } else { current = current.Right; } } if (root == null) { root = newNode; } else { if (newNode.item < parent.item) { parent.Left = newNode; } else { parent.Right = newNode; } } } private int getHeight(){ return findHeight(root); } private int findHeight(Node root){ if(root==null){ return 0; } int leftHeight = findHeight(root.Left); int rightHeight = findHeight(root.Right); return Math.max(leftHeight,rightHeight)+1; } private int getLargestKey(){…
To copy a tree, traverse the tree using an ___ traversal and add each data item visited to the new tree. inorder postorder preorder reorder
II. Project Description Parts Catalog This project builds a parts catalog using a B-tree for storage. Introduction: Today a parts catalog would be built using a database for storage. Databases are very versatile in their ability to store and retrieve data. In this project, you will build a parts catalog system as a single-user system without the use of a database. Instead, you will create a B+-tree and store the parts data in it. Overview: This project consists of two parts: a B+-tree for storing parts data and a user interface for accessing the data. These two parts should be independent, so that changing to another storage system or another user interface is not too difficult. Your project should allow the user to maintain a parts catalog. A flat-file of part data will be provided. Your program should begin by loading data from the flat-file into a B+-tree. Once loaded, the user can query for a particular part number, display the next 10 parts, modify the description of a part, add…
12:34 A cs61a.org Implement add_d_leaves, a function that takes in a Tree instance t and a number v. We define the depth of a node in t to be the number of edges from the root to that node. The depth of root is therefore 0. For each node in the tree, you should add d leaves to it, where d is the depth of the node. Every added leaf should have a label of v. If the node at this depth has existing branches, you should add these leaves to the end of that list of branches. For example, you should be adding 1 leaf with label v to each node at depth 1, 2 leaves to each node at depth 2, and so on. Here is an example of a tree t (shown on the left) and the result after add_d_leaves is applied with v as 5. 3 2 3 2 4 4 5 5 5 Hint: Use a helper function to keep track of the depth! def add_d_leaves(t, v): """Add d leaves containing v to each ng
True or false Complete all questions

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