BST - Removal Algorithm 1. Complete the code of the iterative BST removal method (as seen on slide 9 of the lecture). Complete the • search for the node, and • the removal (case 1, case 2 and case 3) • the cases illustrated here might help you. public boolean remove(int target) { // where the iten will be found. // This nd needs to be removed. BSTNode nd = root; BSTNode parent - null; // parent of the nd to be removed. boolean is left_child = false; // how nd was reached from parent. // search node with nd.data == target, I/ remember the parent, and if left or right path if (nd == null) // target not found, no removal. returm false; else { // found target in nd, three cases for removal. I/ case 1: nd is a leaf, has no children // case 2: nd has 1 child at the left / case 2: nd has 1 child at the right I/ case 3: nd has two 2 children: replace nd by predecessor or by successor Submit your solution as a pdf-file (neat handwriting is okay).
BST - Removal Algorithm 1. Complete the code of the iterative BST removal method (as seen on slide 9 of the lecture). Complete the • search for the node, and • the removal (case 1, case 2 and case 3) • the cases illustrated here might help you. public boolean remove(int target) { // where the iten will be found. // This nd needs to be removed. BSTNode nd = root; BSTNode parent - null; // parent of the nd to be removed. boolean is left_child = false; // how nd was reached from parent. // search node with nd.data == target, I/ remember the parent, and if left or right path if (nd == null) // target not found, no removal. returm false; else { // found target in nd, three cases for removal. I/ case 1: nd is a leaf, has no children // case 2: nd has 1 child at the left / case 2: nd has 1 child at the right I/ case 3: nd has two 2 children: replace nd by predecessor or by successor Submit your solution as a pdf-file (neat handwriting is okay).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![BST - Removal Algorithm
1. Complete the code of the iterative BST removal method (as seen on slide 9 of the
lecture). Complete the
• search for the node, and
• the removal (case 1, case 2 and case 3)
• the cases illustrated here might help you.
public boolean remove(int target) {
// where the item will be found.
// This nd needs to be removed.
BSTNode nd - root;
BSTNode parent - null;
// parent of the nd to be removed.
boolean is left_child - false;
// how nd was reached from parent.
// search node with nd.data == target,
// remember the parent, and if left or right path
if (nd == null)
// target not found, no removal.
return false;
else {
// found target in nd, three cases for removal.
// case 1: nd is a leaf, has no children
// case 2: nd has 1 child at the left
// case 2: nd has 1 child at the right
// case 3: nd has two 2 children: replace nd by predecessor or by successor
}
Submit your solution as a pdf-file (neat handwriting is okay).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36591f5f-f09d-438b-8d4f-237adb008b97%2F6a4f9dd1-ffc7-4ca0-8e76-80f16706f41f%2F7gu5y5j_processed.png&w=3840&q=75)
Transcribed Image Text:BST - Removal Algorithm
1. Complete the code of the iterative BST removal method (as seen on slide 9 of the
lecture). Complete the
• search for the node, and
• the removal (case 1, case 2 and case 3)
• the cases illustrated here might help you.
public boolean remove(int target) {
// where the item will be found.
// This nd needs to be removed.
BSTNode nd - root;
BSTNode parent - null;
// parent of the nd to be removed.
boolean is left_child - false;
// how nd was reached from parent.
// search node with nd.data == target,
// remember the parent, and if left or right path
if (nd == null)
// target not found, no removal.
return false;
else {
// found target in nd, three cases for removal.
// case 1: nd is a leaf, has no children
// case 2: nd has 1 child at the left
// case 2: nd has 1 child at the right
// case 3: nd has two 2 children: replace nd by predecessor or by successor
}
Submit your solution as a pdf-file (neat handwriting is okay).
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