Part A A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H,SO4: H2SO4 (aq) + 2N2OH(aq) → 2H2O(1) + NazSO. (aq) If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution? Express your answer with the appropriate units. HA ? molarity = Value Units Submit Request Answer

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### Part A: Titration Calculation

A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H₂SO₄:

\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]

If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H₂SO₄ solution? Express your answer with the appropriate units.

#### Input Fields
- **Molarity (Value):** [Text Field]
- **Units:** [Drop-down Menu]

#### Action Buttons
- **Submit**
- **Request Answer**

Enter the values and units to solve the problem as prompted:

\[ \text{Molarity (Value)} = \_\_\_\_ \]
\[ \text{Units} = \_\_\_\_ \]

---

In this titration problem, you are given the concentration and volume of NaOH solution and the volume of H₂SO₄ solution. Use the balanced chemical equation to find the molarity of the H₂SO₄ solution.

#### Balanced Equation:
The balanced chemical equation for the reaction between NaOH and H₂SO₄ shows that one mole of H₂SO₄ reacts with two moles of NaOH:

\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]

#### Calculation Steps:

1. **Determine moles of NaOH:**
   \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (L)} \]
   \[ \text{Moles of NaOH} = 0.158 \, \text{M} \times 0.0394 \, \text{L} \]

2. **Use the stoichiometry to find moles of H₂SO₄:
Transcribed Image Text:### Part A: Titration Calculation A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H₂SO₄: \[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \] If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H₂SO₄ solution? Express your answer with the appropriate units. #### Input Fields - **Molarity (Value):** [Text Field] - **Units:** [Drop-down Menu] #### Action Buttons - **Submit** - **Request Answer** Enter the values and units to solve the problem as prompted: \[ \text{Molarity (Value)} = \_\_\_\_ \] \[ \text{Units} = \_\_\_\_ \] --- In this titration problem, you are given the concentration and volume of NaOH solution and the volume of H₂SO₄ solution. Use the balanced chemical equation to find the molarity of the H₂SO₄ solution. #### Balanced Equation: The balanced chemical equation for the reaction between NaOH and H₂SO₄ shows that one mole of H₂SO₄ reacts with two moles of NaOH: \[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \] #### Calculation Steps: 1. **Determine moles of NaOH:** \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (L)} \] \[ \text{Moles of NaOH} = 0.158 \, \text{M} \times 0.0394 \, \text{L} \] 2. **Use the stoichiometry to find moles of H₂SO₄:
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