Part A A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H,SO4: H2SO4 (aq) + 2N2OH(aq) → 2H2O(1) + NazSO. (aq) If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution? Express your answer with the appropriate units. HA ? molarity = Value Units Submit Request Answer
Part A A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H,SO4: H2SO4 (aq) + 2N2OH(aq) → 2H2O(1) + NazSO. (aq) If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution? Express your answer with the appropriate units. HA ? molarity = Value Units Submit Request Answer
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Part A: Titration Calculation
A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H₂SO₄:
\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]
If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H₂SO₄ solution? Express your answer with the appropriate units.
#### Input Fields
- **Molarity (Value):** [Text Field]
- **Units:** [Drop-down Menu]
#### Action Buttons
- **Submit**
- **Request Answer**
Enter the values and units to solve the problem as prompted:
\[ \text{Molarity (Value)} = \_\_\_\_ \]
\[ \text{Units} = \_\_\_\_ \]
---
In this titration problem, you are given the concentration and volume of NaOH solution and the volume of H₂SO₄ solution. Use the balanced chemical equation to find the molarity of the H₂SO₄ solution.
#### Balanced Equation:
The balanced chemical equation for the reaction between NaOH and H₂SO₄ shows that one mole of H₂SO₄ reacts with two moles of NaOH:
\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]
#### Calculation Steps:
1. **Determine moles of NaOH:**
\[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (L)} \]
\[ \text{Moles of NaOH} = 0.158 \, \text{M} \times 0.0394 \, \text{L} \]
2. **Use the stoichiometry to find moles of H₂SO₄:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8345495-5282-4b9a-a515-8a335bc64c34%2Fd1378df4-59ed-4272-b20a-c409e7869f5d%2Foiqo7m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Part A: Titration Calculation
A solution of 0.158 M NaOH is used to titrate 23.5 mL of a solution of H₂SO₄:
\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]
If 39.4 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H₂SO₄ solution? Express your answer with the appropriate units.
#### Input Fields
- **Molarity (Value):** [Text Field]
- **Units:** [Drop-down Menu]
#### Action Buttons
- **Submit**
- **Request Answer**
Enter the values and units to solve the problem as prompted:
\[ \text{Molarity (Value)} = \_\_\_\_ \]
\[ \text{Units} = \_\_\_\_ \]
---
In this titration problem, you are given the concentration and volume of NaOH solution and the volume of H₂SO₄ solution. Use the balanced chemical equation to find the molarity of the H₂SO₄ solution.
#### Balanced Equation:
The balanced chemical equation for the reaction between NaOH and H₂SO₄ shows that one mole of H₂SO₄ reacts with two moles of NaOH:
\[ \text{H}_2\text{SO}_4(\text{aq}) + 2\text{NaOH}(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Na}_2\text{SO}_4(\text{aq}) \]
#### Calculation Steps:
1. **Determine moles of NaOH:**
\[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (L)} \]
\[ \text{Moles of NaOH} = 0.158 \, \text{M} \times 0.0394 \, \text{L} \]
2. **Use the stoichiometry to find moles of H₂SO₄:
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