NaOH(aq) + HCI (aq) →>> NaCl (aq) + H₂O (1)34.90 mL of 0.1002 M NaOH was used to titrate11.00 mL of HCI to the endpoint. Calculate the molof HCI that reacted and the molarity of the HCIsolution.SHOW WORK. Write out the problem on paper showing allconversion factors, unit cancellations, calculations, s.f., etc. Answer thequestions related to the setup and calculation for this problem. Besure to use our periodic table to calculate any molar masses needed(rounded to proper number of decimal places), otherwise your valuesmight be slightly off and answers may be marked as incorrect.Abbreviate units as follows: grams = g, moles = mol, molarity = MEnter where each reactant is placed at the beginning of theexperiment (options are buret or flask):NaOH:HCI:Use the three blanks to enter the number. unit, and substance un ISG$%2 Use the three blanks to enter the number, unit, and substance (in thisorder) that appears in the denominator of the stoichiometryconversion factor.Calculate the mol of HCI that reacted and enter the value only(decimal notation, including proper s.f.).molCalculate the molarity of the original HCI solution and enter the valueonly (decimal notation, including proper s.f.).M

In a acid-base titration, base should be placed in buret and acid should be placed in flask. So,…

+ HCl (aq) (aq) NaOH 34.90 mL of 0.1002 M NaOH was used to titrate 11.00 mL of HCI to the endpoint. Calculate the mol of HCI that reacted and the molarity of the HCI solution. → -> NaCl + H₂O (1) (aq)

+ HCl (aq) (aq) NaOH 34.90 mL of 0.1002 M NaOH was used to titrate 11.00 mL of HCI to the endpoint. Calculate the mol of HCI that reacted and the molarity of the HCI solution. → -> NaCl + H₂O (1) (aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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