Solution Page < 2> of 4Homework 10-2: Compute the net area of each of the given members.Use standard-size bolt holes for all problems.℗ PearsonӨΘΘ3/4 in bolts (Typical)PL 4 × 10O(PL 3/4×10Bolts are○中Copyright 2018, 2012, 2008, 2003 by Pearson Education, Inc.99+AiQ Search

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Answered: Page < 2 > of 4 Homework 10-2: Compute…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question No.3: Determine the maximum tensile force, Pu, that can be applied to the connection shown in figure below based on the bolt strength; assume ASTM A36 steel for the following bolt types in standard holes: Check every limit state. a. 1-in.-diameter A325N, b. 7/8-in.-diameter A490X. 3" 3" 1½" /" plate ½P, P ½P. /" plate
Determine the number of bolts required to develop the full capacity of the double angle tension member shown in the accompanying figure. Use double row of bolts without stagger. Dead Load = 10% Live Load = 90% Angle Steel is A572 Grade 50 Bolt Diameter = 3/4 in Type of Connection is A325-X, Bearing Type, threads excluded from shear planes.
Situation 9: A steel plate is 250 mm wide and 10 mm thick with 4 bolts (22mm dia) cut into the plate as shown. Hole diameter-diameter of bolt + 2 mm Use Fy-248 MPa and Fu-400MPa Giver $1-70mm, 52-70mm, 53-80mm,81-70mm82-70mm,83-70mm HR T+ H 1. Which of the following nearly gives the Design Strength Tu? +0 FO 11 4 43
Question 17 2L5x3x7mm tension momber is connocted to a gussot plate by 16-mm-diameter bolts as shown in the figure, Given that e= 30 mm, s= 50 mm, Fy =345 MPa and Fu=402 MPa, caicukato the following 2 L5 x3x % LLBD (two angles, long legs back-to-back) A242 stoel 60 mm e (am) (mn) e (mm) 55 Not area in shoar for a single angle under block shear lailue, Ariv mm? 56. Not area in tension for a single anglo under.block shoar failuto Arit = 57. Norninal block shear strongth in kN of the double angle Use Ups 10, Pn INPUT ALL ANSWERS AS WHOLE NUMBER
01:) Determine the design tensile strength for the member and bearing type connections if A325 3/4-in standard bolts are used as shown below, threads are excluded for shear plane (Fy =36ksi and Fu=58ksi). Note: don't consider the slip critical connection in your calculations, E of steel is 29000ksi 13 in 13 in 13 in 13 in | 2 in 3 in 12 in 3 in PL를 x 12 PL 1 x 12 P/2 P/2 E PL x 12
The bolted connection shown is a bearing type connection. Which of the following best gives the shearing capacity, ØRn. of the bolts? Consider threads excluded from shear plane and deformation at bolt hole is a design consideration. Standard size holes. PL350x12mm = 250 MPa C250x22.8 70 114 M20 A490 70 40' 60' 60 '40 SECT. A d tw bf tf Mm 15.8 mm^2 mm mm mm mm C250x22.8 2880 254 6.1 65 11.1 Ix(10^6) Sx(10^3) ly(10^6) Sy(10^3) Zx(10^3) Zy(10^3) rx ry mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 27.7 218 98.1 0.912 18.5 18.5 257 40.3 O 424.8 KN O 1,102.7 KN O 3,770.7 KN O 1,637.1 KN
The bolted connection shown in Figures is connected with 3/4-in-diameter bolts in standard holes. The plate material is A36 steel. By using strength level design (LRFD), find the available tensile strength of the plates. u=0.8 (5)-¾" bolts 4" C12× 20.7 | 4½" ,3" , 4½" |
Subject: Steel design- Bolted Steel Connection *Use NSCP 2015 formula/guide to solve this problem *Use Handwritten
a] Compute LRFD 6.) Compute ASD CIVIL STEEL DESIGN ENGINEERING- BOLTED CONNECTION Sample Problem 5: The 175 x 100 x 16 mm angle shown connected to a gusset plate with three 25 mm bolts (A490) when threads are excluded from shear planes. The angle consists of A36 steel. Properties of 4 175 x 100 x 16 A36 Steel Properties of A490 bolts A = 4181 mm² t = 16 mm Fy = 248 MPa F₁ = 400 MPa Fy = 276 MPa Nominal hole dia. = 27 mm 75 T+ 100 Gusset Plate 100 F 100
If the connection is bolted connection, find the maximum load that can carried by the connection if the type of bolts is A325 threaded in the plane of shear. The bolt diameter is 5/8" and the thickness of gusset plate is 3/4". PL10x3/4 11.5| 3 | Pu Pu 10 3 1.5" 00 A36 Steel 2MC12X31 Section a-a
The plate splice shown in the figure below has 9 – 3/4 inch diameter A325-N type bolts (Group A, N type) on each side. Based on the shear strength of bolts only, the maximum Pu that can be applied to the splice is equal to: Group of answer choices 202 kips 322 kips 161 kips 405 kips
A bolted connection shown is made up of 2L150 x 100 x 9.5 mm. The angle is made of A-36 steel and the bolts have diameter of 22 mm. Properties of 2L150 x 100 x 9.5 mm: A = 4660 mm2 t = 9.5 mm Fy = 248 MPa Fu = 400 MPa Properties of 20 mm A-325 bolts: Fu = 400 MPa 50 50 50 50 50 50,50 힝힝이어 Gusset Plate 9.5mm 100mm Gusset Plate 100mm 31.25 62.5 T 56.25 a. Nominal dimension of hole diameter, dn = 25 mm b. Determine the ultimate shear capacity (kN) of the connection. c. Determine the ultimate tearing capacity (kN) of the connection if the shear lag factor, U = 0.75.

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Page < 2 > of 4 Homework 10-2: Compute the net area of each of the given members. Use standard-size bolt holes for all problems. ℗ Pearson Ө Θ Θ 3/4 in bolts (Typical) PL 4 × 10 O (PL 3/4×10 Bolts are ○中 Copyright 2018, 2012, 2008, 2003 by Pearson Education, Inc. 99+ Ai Q Search