Answered: The position of a particle is defined…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given the eulerian velocity-vector field V = 3ti + xzj + tyk find the acceleration of a particle.
1.The position of a particular particle as a function of is given by r=(8.5t i+5.6j-2t 2k )m (a) Determine the particle’s velocity and acceleration as a function of time. (b) Find the instantaneous velocity and acceleration of the particle at t=3.0 s. Question 2 . At t=0, a particle starts from rest and moves in the xy space with an acceleration a=(4 i+6 2 j)m/s . Determine (a) the velocity and position of the particle as a function of time. (b) evaluate the speed and position of the particle at t=5.0 s.
The velocity of a particle moving along the x-axis is given by the function v (t) = 2t^3 + 15 for t > 0. Find the total distance traveled by the particle from t=2 to t=4.
Q3: A particle moves along the x- axis according to the equation (x-14-7t+t^2+t^3 ), where (x) in meter and (t) in seconds. At (t=7 sec) Find (a) The position of the particle (b) It's velocity (c) It's .acceleration
The position of a particle moving along the x-axis is given by (X(t)=3t+2t^3 ). Find the acceleration a= 3+6t^2 ( m/sec2) 12 (m/sec2) 12 t ( m/ssec2) Object's mass is 15 kg is resting on a table. An external force ( 10 N) act with angle ( 30) on this object. Find the minimum force let it moving. ( g=10m/sec2) * 5 N 150 N 8.66 N
The velocity of a particle which moves along the s-axis is given by s = 46 - 6t2 m/s where t is in seconds. Calculate the displacement As of the particle during the interval from t = 1sto t = 3.4 s. Answer: As = i
DYNAMICS OF RIGID BODIES
The motion of a particle is defined by x = 6t – 2t³ – 12² – 3t + 3, where x and t are expressed in meters and seconds, respectively. Determine the time, the position, and the velocity when a = 0. -
The motion of a particle is defined by the relation x = 2t4 – 6t3 + 3t + 3, where x and t - are expressed in meters and seconds, respectively. Determine the time, the = 0. position, and the velocity when a = 0.
EXAMPLE (2) A bar of uniform cross sectional area 100mm2 is subjected to forces as shown in Fig . Calculate change in length of the bar. Take E=2*105 N/mm?. A C 1kN 5KN 6KN 2kN 300mm 400mm 600mm
The position of a particle is defined by s=6t²-8+40cosπ where s and t are expressed in inches and seconds respectively. Determine the position,velocity and acceleration when t=6 seconds
The motion of a particle is defined by x = 6t"4 - 2t°3 - 12t^2 + 3t + 3, when x and t are expressed in meters and seconds, respectively. • When a = 0, determine the time • When a= 0, determine the velocity When a = 0, determine the position

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The position of a particle is defined by s=6t²-8+40cosπt.find the position , velocity and acceleration of the particle at time t=6 seconds