P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm
P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm
through a shaft with a 30-mm diameter.
Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]:
2π
P = Tw=
Tn= Tn/9549
60 × 1000
Note: in the formula, P is in kW, T is in Nm, n is in rpm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3513363-cb6f-4339-8b85-3b7b98137f18%2Fda8256cf-bee5-46d4-b535-8595b55aea34%2Fclx83i1_processed.png&w=3840&q=75)
Transcribed Image Text:P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm
through a shaft with a 30-mm diameter.
Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]:
2π
P = Tw=
Tn= Tn/9549
60 × 1000
Note: in the formula, P is in kW, T is in Nm, n is in rpm
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