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P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm

P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm
Transcribed Image Text:P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm
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