P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm

Elements Of Electromagnetics
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P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm
through a shaft with a 30-mm diameter.
Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]:
2π
P = Tw=
Tn= Tn/9549
60 × 1000
Note: in the formula, P is in kW, T is in Nm, n is in rpm
Transcribed Image Text:P.2) Using an allowable shear stress of 50 MPa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter. Hint: (Power) = (Torque)(Angular velocity) [See Lec_02, or pg. 117 eq. (3-44)]: 2π P = Tw= Tn= Tn/9549 60 × 1000 Note: in the formula, P is in kW, T is in Nm, n is in rpm
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