Pn = P. (1 +r) mWDn = Pn x Cn x fn + WDT(n)P = 0.5CpAppu,3r= 1+ 0.5 (a x b x h)TY UTM%RCo-CtTMx 100%CoAH, (R, + R,), AH, (R, +R,)¸ AH, (R; + R,UTMR =%DHH 2HDetention timeDynamic Viscosityutes1.14 x 10 N/mt P.-P.(1+r)" WD. = P.x C.x.+ WDP-0SCoApuA 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are asfollows:P-GuVr-I+0.5 (ax b x h)%R =x 100%AH, (R, +R,) AH, (R, +R,) AH, (R, +R, )R, =Number of paddlesNumber of plates per paddleArea of each plateCoefficient of dragRelative velocity of paddleDetention time4H24Q Zoom0.6 m?!!1.8%3D0.55 m/s%3D25 minutes%3DDynamic ViscosityDensity of water1.14 x 10 3 Ns/m²1000 kg/m3Compute the power required for the tank.A1437 WB90 W4 752 WD2614 W

P.-P.(1+1)" wD.P.C WD A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are a follows: P-GV r-+05 (axb x h) R x 100% AH, (R, +R,) AH, (R, +R,) AH, (R, + R,) H 2 Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 %3D R, = H 2 4 %3D Q Zoom 0.6 m2 %3D 1.8 %3D 0.55 m/s %3D 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10 3 Ns/m2 1000 kg/m3 %3D Compute the power required for the tank. A 1437 W 90 W 4 752 W 2614 W

P.-P.(1+1)" wD.P.C WD A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are a follows: P-GV r-+05 (axb x h) R x 100% AH, (R, +R,) AH, (R, +R,) AH, (R, + R,) H 2 Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 %3D R, = H 2 4 %3D Q Zoom 0.6 m2 %3D 1.8 %3D 0.55 m/s %3D 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10 3 Ns/m2 1000 kg/m3 %3D Compute the power required for the tank. A 1437 W 90 W 4 752 W 2614 W

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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