Pn = Po (1 + r) mWDn = Pn x Cn x fn + WDT(n)P = 0.5CpAppU,UTM Ur=1+ 0.5 (a x b x h)TM&UTM%R = °°=t x 100%P = G²uV%3DIMCoUTMAH, (R, + R,) AH, (R, +R;)%3D, AH, (R; + R, )(R, + R, )H4HUTM 2HDetention time114 103 P-0SCApu,A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are asP.-P.(I+r) wo. P.xCx WDnfollows:P-G'uVr-1+05 (ax b x h)R =Sx 100%Number of paddlesNumber of plates per paddleArea of each plateCoefficient of dragRelative velocity of paddleDetention time4AH, (R, + R,) AH, (R, +R,) ¸ AH, (R, + R, )R2%3DH.H4Q Zoom0.6 m2%3!1.80.55 m/s25 minutes%3D1.14 x 10 3 Ns/m²1000 kg/m³Dynamic Viscosity%3DDensity of water%3DCompute the volume for each tank in m3.B1 5001042D260375

Detention time=25min Discharge=60MLD

A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are as follows: P.-P.(1+1) wo. P.xGxt WDn P-0SCApu P-GuV r-+05 (axb x h) R= x 100% Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 AH, (R, +R,) AH, (R, +R) AH, (R, +R,) 2 H %3D 4 Q Zoom 0.6 m2 !! 1.8 !! 0.55 m/s 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10-3 Ns/m² 1000 kg/m %3D Compute the volume for each tank in m3. 1 500 1042 260

A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are as follows: P.-P.(1+1) wo. P.xGxt WDn P-0SCApu P-GuV r-+05 (axb x h) R= x 100% Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 AH, (R, +R,) AH, (R, +R) AH, (R, +R,) 2 H %3D 4 Q Zoom 0.6 m2 !! 1.8 !! 0.55 m/s 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10-3 Ns/m² 1000 kg/m %3D Compute the volume for each tank in m3. 1 500 1042 260

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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