A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are as follows: P.-P.(1+1) wo. P.xGxt WDn P-0SCApu P-GuV r-+05 (axb x h) R= x 100% Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 AH, (R, +R,) AH, (R, +R) AH, (R, +R,) 2 H %3D 4 Q Zoom 0.6 m2 !! 1.8 !! 0.55 m/s 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10-3 Ns/m² 1000 kg/m %3D Compute the volume for each tank in m3. 1 500 1042 260
A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are as follows: P.-P.(1+1) wo. P.xGxt WDn P-0SCApu P-GuV r-+05 (axb x h) R= x 100% Number of paddles Number of plates per paddle Area of each plate Coefficient of drag Relative velocity of paddle Detention time 4 AH, (R, +R,) AH, (R, +R) AH, (R, +R,) 2 H %3D 4 Q Zoom 0.6 m2 !! 1.8 !! 0.55 m/s 25 minutes %3D Dynamic Viscosity Density of water 1.14 x 10-3 Ns/m² 1000 kg/m %3D Compute the volume for each tank in m3. 1 500 1042 260
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:Pn = Po (1 + r) m
WDn = Pn x Cn x fn + WDT(n)
P = 0.5CpAppU,
UTM U
r=1+ 0.5 (a x b x h)
TM&UTM
%R = °°=t x 100%
P = G²uV
%3D
IM
Co
UTM
AH, (R, + R,) AH, (R, +R;)
%3D
, AH, (R; + R, )
(R, + R, )
H
4
H
UTM 2
H
Detention time
114 103
Transcribed Image Text:P-0SCApu,
A 60 MLD water treatment plant has 4 mechanical flocculators. The design criteria for each flocculator are as
P.-P.(I+r) wo. P.xCx WDn
follows:
P-G'uV
r-1+05 (ax b x h)
R =Sx 100%
Number of paddles
Number of plates per paddle
Area of each plate
Coefficient of drag
Relative velocity of paddle
Detention time
4
AH, (R, + R,) AH, (R, +R,) ¸ AH, (R, + R, )
R
2
%3D
H.
H
4
Q Zoom
0.6 m2
%3!
1.8
0.55 m/s
25 minutes
%3D
1.14 x 10 3 Ns/m²
1000 kg/m³
Dynamic Viscosity
%3D
Density of water
%3D
Compute the volume for each tank in m3.
B
1 500
1042
D
260
375
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