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H= Ht= Nf= Nd= find: - a) total discharge, b) P.W.P.. at A anc Q=k - H - L Nd c) head to satisfy f Q= F.S. Н Ah i. = AL G. -1 i ミと Nd 1+e ic= ie= FS= Ht - Na(point)"Ah he (point) = h, (point) - h. (point) h, (point) u or P.W.P. (point he (point) Yw point he ht hp PWP a b cl cm cr d e B, actor of safety equal to 2 against boiling. y= 19 kN/m3 9. k= 0.001 bd m/day r 04 k0.0 impermeable layer 10 15 20

H= Ht= Nf= Nd= find: - a) total discharge, b) P.W.P.. at A anc Q=k - H - L Nd c) head to satisfy f Q= F.S. Н Ah i. = AL G. -1 i ミと Nd 1+e ic= ie= FS= Ht - Na(point)"Ah he (point) = h, (point) - h. (point) h, (point) u or P.W.P. (point he (point) Yw point he ht hp PWP a b cl cm cr d e B, actor of safety equal to 2 against boiling. y= 19 kN/m3 9. k= 0.001 bd m/day r 04 k0.0 impermeable layer 10 15 20

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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H= Ht= Nf= Nd= find: - a) total discharge, b) P.W.P.. at A anc c) head to satisfy f Q=k - H - L Nd Q= ic F.S. G,-1 H/ Ah /Nd i = %3D 1+e AL ic= ie= FS= h (ooint= Ht - Na(point)"Ah h, (point) = h, (point) he (point) u or P.W.P. (ooint= h, (point) Yw Ipoint he ht hp PWP a b cl cm cr 1B, actor of safety equal to 2 against boiling. y= 19 kN/m3 k= 0.001 G= 2 r 04 k6.0 m/day bld impermeable layer 10 15 20
Transcribed Image Text:H= Ht= Nf= Nd= find: - a) total discharge, b) P.W.P.. at A anc c) head to satisfy f Q=k - H - L Nd Q= ic F.S. G,-1 H/ Ah /Nd i = %3D 1+e AL ic= ie= FS= h (ooint= Ht - Na(point)"Ah h, (point) = h, (point) he (point) u or P.W.P. (ooint= h, (point) Yw Ipoint he ht hp PWP a b cl cm cr 1B, actor of safety equal to 2 against boiling. y= 19 kN/m3 k= 0.001 G= 2 r 04 k6.0 m/day bld impermeable layer 10 15 20
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