Overall Reaction: Cl2(g) + CHCI3(g) → HCI(g) + CCl«(g) Experimental Rate Law = k[CI]!/2[CHCI3] Proposed Mechanism: 1. C2(g) E→ 2CI(g) 2. Cl(g) + CHCI3(g) → HCI(g) + CCI3(g) 3. Cla(g) + Cl(g) →Cla(g) fast slow fast

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1
The gas phase reaction of chloroform is described by the following equation, experimental
rate law and proposed mechanism.
(a.) Does this proposed mechanism agree with the overall reaction?
(b.) What intermediates are present in this reaction?
(c.) Does the experimental rate law agree with the mechanism provided?
(d.) Write the overall reaction rate constant in terms of the rate constants of the elementary
steps.
NOTE: The rate law should have Cl2 not Cl in the brackets. The experimental rate law will be
k[C12]^(1/2)[CHC13]. Please make this correction. (Non-anonymous questionO)
(20 Points)
%3D
Overall Reaction: Cl2(g) + CHCI3(g) → HCI(g) + CCl4(g)
Experimental Rate Law = k[CI]!/2[CHCI3]
Proposed Mechanism:
1. Cl2(g) E→ 2CI(g)
2. Cl(g) + CHCI3(g) → HCI(g) + CCI3(g)
3. Cl3(g) + Cl(g) →CCI«(g)
fast
slow
fast
Transcribed Image Text:1 The gas phase reaction of chloroform is described by the following equation, experimental rate law and proposed mechanism. (a.) Does this proposed mechanism agree with the overall reaction? (b.) What intermediates are present in this reaction? (c.) Does the experimental rate law agree with the mechanism provided? (d.) Write the overall reaction rate constant in terms of the rate constants of the elementary steps. NOTE: The rate law should have Cl2 not Cl in the brackets. The experimental rate law will be k[C12]^(1/2)[CHC13]. Please make this correction. (Non-anonymous questionO) (20 Points) %3D Overall Reaction: Cl2(g) + CHCI3(g) → HCI(g) + CCl4(g) Experimental Rate Law = k[CI]!/2[CHCI3] Proposed Mechanism: 1. Cl2(g) E→ 2CI(g) 2. Cl(g) + CHCI3(g) → HCI(g) + CCI3(g) 3. Cl3(g) + Cl(g) →CCI«(g) fast slow fast
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