Find the rate law for the reaction 2 N205(g) – 4 NO2(g) + O2(g) based on the proposed mechanism: NO2 + NO3 NO2 + O2 + NO - 3 NO2 N205 fast NO2 + NO3 NO + N205 slow fast O rate = k[ N205)° rate = k[ N2O5)? O rate = k[ NO2][ NO3] O rate = k[ N205) %3D

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Find the rate law for the reaction 2 N205(g) → 4 NO2(g) + O2(g) based on the proposed mechanism:
N205
NO2 + NO3
fast
NO2 + NO3
NO + N205
NO2 + 02 + NO
slow
3 NO2
fast
rate = k[ N205]°
rate = k[ N205)?
rate = k[ NO2][ NO3]
O rate = k[ N205]
Transcribed Image Text:Find the rate law for the reaction 2 N205(g) → 4 NO2(g) + O2(g) based on the proposed mechanism: N205 NO2 + NO3 fast NO2 + NO3 NO + N205 NO2 + 02 + NO slow 3 NO2 fast rate = k[ N205]° rate = k[ N205)? rate = k[ NO2][ NO3] O rate = k[ N205]
Expert Solution
Step 1

The rate of the overall reaction depends on the rate of the slow step only.

Therefore, the rate law expression is given in terms of the concentrations of the components present in slow step only.

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