One kilogram of a real gas (Gas #1) (M=32 kg/kmol) is at pressure 5.842 MPa and in a spherical tank of diameter 0.2315 m. Find the temperature using van der Waals equation of state, consider a =6.7 atm (m³/kmol)2 and b=0.056 m³/kmol. 173.15 K 273.15 K 393.7 K 593.7 K

One kilogram of a real gas (Gas #1) (M=32 kg/kmol) is at pressure 5.842 MPa and in a spherical tank of diameter 0.2315 m. Find the temperature using van der Waals equation of state, consider a =6.7 atm (m³/kmol)2 and b=0.056 m³/kmol. 173.15 K 273.15 K 393.7 K 593.7 K

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter1: Gases And The Zeroth Law Of Thermodynamics

Section: Chapter Questions

Problem 1.32E

See similar textbooks

Related questions

Q: For problems 1 through 3 below, the initial state of 1 mole of an ideal gas is P₁ = 3 atm, V₁ = 1…

A: P1 = 3 atmV1 = 1 LU1 = 456 JP2 = 2 atmV2 = 3 LU2 = 912 JThe gas expands to a volume of 3 L keeping…

Q: Find the following values for the real gas equation (van der Waals). de (ap), =?,r =?,)p =1 av

A: According to Van der Waals equation, where P = pressure V = volume n = moles R = gas constant =…

Q: Ised a standard pressure of 02(g), which is not very reasonable even in air (air is only 20% 02). A…

A: Le Chatelier’s principle states that when there is a change in the temperature, volume, pressure, or…

Q: You have 17.14 lb of CO2 in a 47.26 ft3 fire extinguisher tank at 50degC. Assuming that the ideal…

Q: 2. A 20. m long gas pipeline made out of Schedule 40. PVC pipe that is 2.66 cm in diameter is used…

A: We will use the ideal gas equation to determine the maximum number of moles of butane that the pipe…

Q: What Is The Ideal-Gas Equation of State?

A: Gas equations can be written as; V∝1T (Boyle's law)V∝T (Charles…

Q: A quantity of gas in a piston cylinder has a volume of 0.466 m3 and a pressure of 200 Pa. The piston…

A: Initial Volume = V1 = 0.466 m3 Initial Pressure = P1 = 200Pa Final Volume , V2 = 0.245 m3…

Q: The gas inside a cylinder expands against a constant external pressure of 0.991 atm from a volume of…

A: Since, there is no heat loss. Hence all the work done by gas will be transferred to the benzene.

Q: Calculate the actual pressure for a non-ideal system for 1.00 mole of carbon dioxide gas in 3.00 L…

A: Given, Moles, n = 1 mol Volume, V = 3.00 L Temperature, T = 0 oC = 273 K a = 3.59 L2·atm/mole2 b =…

Q: A N2 gas is pumped into a container with 39.6 L volume at 298.15 K and the final pressure reads 15.3…

Q: The van der Waals equation of state for a real gas is n²a P+ y2 nb| = nRT At what pressure will 1.00…

A: Given, Temperature(T) = 298 K moles(n) = 1 mol volume(V) = 10 L a = 2.253 atm L2 /mol2 b = 0.04278…

Q: A plot of pressure-volume isotherms for an ideal gas at two different temperatures is shown below.…

A: Given that : We have to calculate the ∆Sgas if 1 mole of the gas cycles through all three processes…

Q: look for critical parameters and calculate its molar volume using the real gas equation of states at…

Q: 1. In a 100mL sealed flask, 0.1 g of H2 gas reacts with 0.15 g of N2 gas to generate NH3 gas at 25…

A: The reaction between H2 and N2 is written as, N2(g) + H2(g) → NH3(g) Multiply NH3(g) with 2 and…

Q: Five liters of nitrogen gas initially at T = 27 degrees C and P = 1 atm are heated to T = 127…

A: Here 5 L of N2 gas initially at 27°C and P=1atm is heated to 127°C .We have to determine w, ∆E ,∆H…

Q: This figure (Figure 1)shows a container that is sealed at the top by a movable piston. Inside the…

A: Given:Initial conditionvolume, V1=1.00 LPressure, P1=1.01 barTemperature, T1 = 20oC = 20+273 K…

Q: 1 mole of monoatom gas at 25°C cooled, then allowed to expand from 1.0OL to 10.00L at external…

Q: One mol of O2(g) undergoes a transformation from the initial state T 300 K and %D V1 20.0 L to the…

A: Gases that obey the van-der-waals equation of state are called as van-der-waals gas. The…

Q: mpressed to 3 cu.m, what is the resulti ssure assuming isothermal condition= a abs? (UP TO THREE…

A: Given, V1 = 8 cu.m V2 = 3 cu.m P1 = 200 kPa

Q: Determine the pressure change when a constant volume of gas at 101.3 kPa is heated from 27°C to…

A: Given: P1 = 101.3 kPa T1= 27 °C = 27+273 = 300 K T2 = 38 °C = 38+273 = 311 K To determine: Pressure…

Q: A 3.5 L canister at 20°C under a pressure of 120 kPa is compressed to a volume of 700 mL. Determine…

Q: Complete the ideal gas tables. All answers shall be in 4 decimal places. P (kPa) 125 p (kgm/m³) o…

A: The value of ideal gas constant for a gas is: R=8.314 JK.molin terms of molar mass (MW) of a gas…

Q: Consider the initial conditions of a gas: Variable Initial Value 400. K V 250. L 3.30 atm Determine…

Q: A gas is heated from 263K to 298K. The volume is increased from 24.0L to 35.0L. If the original…

Q: An ideal gas (the system) is contained in a flexible balloon at a pressure of 1 atm and is initially…

A: When the surroundings deliver heat to the system , the reaction is defined as an endothermic…

Q: When 0.5 g of a liquid is completely evaporated and collected in a liter manometer, the pressure is…

Q: One type of gas mixture used in anesthesiologyis a 50%/50% mixture (by volume) of nitrous oxide…

A: (a) This process is an adiabatic expansion, hence this is an isochoric process in which the pressure…

Q: Initial Pressure = 125 kPa, Initial Volume = 125 mL, Final Pressure = 100. kPa, Final Volume = 100.…

A: Given that : P1 = 125KPa V1 = 125ml P2 = 100KPa T2 = 75.0°C = 75.0°C + 273= 348K V2 = 100.0mL…

Q: 4. The equation of state for a van der Waal's gas is: RT Vm-b p= a V² m 2 where Vm is the molar…

A: The expression for internal pressure can be derived from internal energy as shown below: dU = TdS…

Q: 2.20 mol of N, at 12.0"C and 6.45 bar undergoes a transformation to the state described by 335 "C…

Q: A canister of pressurized gas has a mass of 10.0000 g. A small amount of gas is released and…

A: If we assume the condition of ideal gas,then we will use the formula of ideal gas equation-…

Q: given: A real gas has the equation of state Z = 1 + B’ p + C’ p2 at 270 K where B’ = - 0.04135 atm-1…

A: Given the equation Z= 1 + B'P + C'P2 and the values of constants, we can plot Z versus P using Excel

Q: A storage tank 55 m³ in volume is filled initially with CO₂ at a pressure of 51.96 atm and the…

Q: Two flasks of equal volume are connected by a narrow tube (of negligible volume). Initially, both…

A: It is given that, Initial Temperature = 27°C = 300.15 K Initial Pressure = 50000 pa = 0.5 atm…

Concept explainers

Kinetic-Theory of Gases

Kinetic theory of gases is the model or method which was developed in the 19th century by Maxwell and Boltzmann. This is possible as the interatomic force which is of short-range forces that are important for solids and liquids can be neglected for gases. This theory or gas law gives a molecular interpretation of the pressure and temperature of a gas and is consistent with gas laws and Avogadro’s hypothesis. This theory is very helpful to correctly explain the specific heat capacities of many gases, kinetic energy and it also explains the transport qualities such as viscosity, thermal conductivity, and diffusion with molecular parameters. As stated in the kinetic-molecular theory, the temperature of a substance or gas particle is related to the average kinetic energy of the particles of that substance. When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles, called average kinetic energy.

Question

One kilogram of a real gas (Gas #1) (M=32 kg/kmol) is at pressure 5.842 MPa and
in a spherical tank of diameter 0.2315 m. Find the temperature using van der Waals
equation of state, consider a =6.7 atm (m³/kmol)2 and b=0.056 m³/kmol.
173.15 K
273.15 K
393.7 K
593.7 K

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Under what conditions of temperature does a Redlich-Kwong gas behave like an ideal gas? Use the Redlich-Kwong equation of state to justify your answer.
Table 1.4 show that the second virial coefficient B for He is negative at low temperature, seems to maximize at a little over 12.0 cm3/mol, and then decreases. Do you think it will become negative again at higher temperatures? Why is it decreasing?
At the critical point for carbon dioxide, the substance is very far from being an ideal gas. Prove this statement by calculating the density of an ideal gas in g/cm3 at the conditions of the critical point and comparing it with the experimental value. Compute the experimental value from the fact that a mole of CO2 at its critical point occupies 94 cm3.
The Berthelot equation of state for one mole of gas is p=RTV-b-aTV2 Where a and b are constants determined experimentally. For NH3g, a = 741.6 atm. L2. K and b = 0.0139 L. Calculate p when V=22.41L and T = 273.15K. How much does the pressure vary from p as predicted by the ideal gas law?
What is the value of FP for a sample of gas whose temperature is -33.0 C and volume is 0.0250 L? What temperature is required to change the volume to 66.9 cm3?
Use the ideal gas law to demonstrate the cyclic rule of partial derivatives.
A refrigerator contains approximately 17cubic feet, or about 480 liters, of air. Assuming it acts as an ideal gas with a molar CV of 12.47 J/mol.K, what is the change in U in cooling the air from normal room temperature 22C to refrigerator temperature 4C? Assume an initial pressure of 1.00 atm.
the answer of part A is 0.721
Physical Chemistry 1
Can someone please explain how to solve this problem? You should get an answer of 5096.4.
One mol of O2(g) undergoes a transformation from the initial state T1 300 K and V1 20.0L to the final state T2 400 K and V2 2.0 L. In this regime O2(g) is reasonably well described by the van der Waals equation of state, with constants 1.364 atm L? mol-2 and b = 3.19 × 10-2 L mol-. Also in this temperature range a = the molar heat capacity at constant volume of O2(g) has the approximately constant value 20.8 J K-l mol-1. Recalling that for a van der Waals gas n? a Əv T V2 ' what is the internal energy change AU of the gas in the transformation (T1, V1) –→ (Тэ, V2)?
4. The equation of state for a van der Waal's gas is: RT V-by², where Vm is the molar volume, V/n. p= m a m Starting with an expression for U(S,Vm), derive an expression for the internal pressure, TT, and calculate its change when a van der Waal's gas with a = 4.14 atm L²mol-2 and b = 5.15 x 10-2 Lmol-¹ is cooled from 200°C to 10°C.