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(Molar Mass of CO₂)

(Molar Mass of CO₂)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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oles of CO₂ = (Mass of CO₂) + (Molar Mass of CO₂) 0.489/44.01 = = 0.0 Molar Volume = VSTP + Moles of CO₂ Percent error = | 0.233/0.0111 = 20.99 L/mol experimental value-true value true value True value = 22.4 L/mol 0.01119 | x 100 -22.4 20.99 22.4 - 6.29% *100
Transcribed Image Text:oles of CO₂ = (Mass of CO₂) + (Molar Mass of CO₂) 0.489/44.01 = = 0.0 Molar Volume = VSTP + Moles of CO₂ Percent error = | 0.233/0.0111 = 20.99 L/mol experimental value-true value true value True value = 22.4 L/mol 0.01119 | x 100 -22.4 20.99 22.4 - 6.29% *100
ere's the second problem. You are doing an experiment in a laboratory that is 30.ºC and 1.080 atm of pressure. You take a 0.240L flask that weighs 98.005g and fill it with CO₂. After it is filled it weighs 98.206g. Calculate the molar volume of the CO₂! VSTP = P₁V₁T STP T1PSTP 1.080 * 0.240* 273 303*1 = 0.233L 1.200 * 0.240 = 0.2889 0.4899 98-206-98-005 +0.288 = 0.4 0.489/44.81 = 0.0111mol.com 0-233/0.0111 = 20.99 L/mol Mass of air = (density of air)(volume of flask) 1.200 * 0.240 = 0. 0.2889 Mass of CO₂ = (Mass of flask filled with CO₂) - (Mass of empty flask) + (Mass of air) 92-206-98·005 +0.288 = 0 0.4899
Transcribed Image Text:ere's the second problem. You are doing an experiment in a laboratory that is 30.ºC and 1.080 atm of pressure. You take a 0.240L flask that weighs 98.005g and fill it with CO₂. After it is filled it weighs 98.206g. Calculate the molar volume of the CO₂! VSTP = P₁V₁T STP T1PSTP 1.080 * 0.240* 273 303*1 = 0.233L 1.200 * 0.240 = 0.2889 0.4899 98-206-98-005 +0.288 = 0.4 0.489/44.81 = 0.0111mol.com 0-233/0.0111 = 20.99 L/mol Mass of air = (density of air)(volume of flask) 1.200 * 0.240 = 0. 0.2889 Mass of CO₂ = (Mass of flask filled with CO₂) - (Mass of empty flask) + (Mass of air) 92-206-98·005 +0.288 = 0 0.4899
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