2.20 mol of N, at 12.0"C and 6.45 bar undergoes a transformation to the state described by 335 "C and 1.95 bar. Part A Calculate AS -30.81 - 11.87 x 1o+2.3968 × 10-*- 1.0176 x 10E 1x 104 Express your answer with the appropriate units
2.20 mol of N, at 12.0"C and 6.45 bar undergoes a transformation to the state described by 335 "C and 1.95 bar. Part A Calculate AS -30.81 - 11.87 x 1o+2.3968 × 10-*- 1.0176 x 10E 1x 104 Express your answer with the appropriate units
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![2.20 mol of N3 at 12.0 °C and 6.45 bar undergoes a transformation to the state described by 335 "Cand 1.95 bar.
Part A
Calculate AS
Cr
3/ K)
- 30.81 - 11.87 x 10 +2.3968 x 10--1.0176 x 10-
Express your answer with the appropriate units.
J
AS - 48.86
K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af7ea5e-f24c-4b28-85bd-eb078489138b%2Ff1f3e3ee-0650-4f4c-81ea-aaa9d31ae658%2Fm18052w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2.20 mol of N3 at 12.0 °C and 6.45 bar undergoes a transformation to the state described by 335 "Cand 1.95 bar.
Part A
Calculate AS
Cr
3/ K)
- 30.81 - 11.87 x 10 +2.3968 x 10--1.0176 x 10-
Express your answer with the appropriate units.
J
AS - 48.86
K
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