Path ps img.WsomulaQUESTION 7On a random cross medical checkup in Muscat airport, the statistic shows 45% of the travelers are form region A, 35% are form regionB, and 20% are form region C. The Medicine doctors have found that 6% of the travelers form region A, 7% of the travelers form regionB, and 5% of the travelers form region C are infected by COVID-19 One week later, an infected traveler went for recheck-up. Find theprobability helshe region A?For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).T TTT Paragraph v ArnalvE- E - T回i%会T T,eO S. OMashups - 1 « O e囲陶盟重Words 0PathClick Save and Submit to save and submit. Click Save All Answers to save al aswers.Save A

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Description: Path ps img.WsomulaQUESTION 7On a random cross medical checkup in Muscat airport, the statistic shows 45% of the travelers are form region A, 35% are form regionB, and 20% are form region C. The Medicine doctors have found that 6% of the travelers f

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Step 1

Based on the provided information, the known values are;

$P (R e g i o n A) = 0.45; P (R e g i o n B) = 0.35; P (R e g i o n C) = 0.20 P (I n f e c t e d | R e g i o n A) = 0.06; P I (n f e c t e d | R e g i o n B) = 0.07; P (I n f e c t e d | R e g i o n C) = 0.05$

Bayes’ rule:

If $A_{1}, A_{2}, . . ., A_{k}$ are k mutually exclusive and exhaustive events, such that the sum of the probability values of the events is 1 and there is an observed event B, then,

$\begin{array}{rcl} P (A j | B) & = & \frac{P (A j \cap B)}{P (B)} \\ = & \frac{P (A_{j}) P (B | A_{j})}{P (A_{1}) P (B | A_{1}) + P (A_{2}) P (B | A_{2}) + . . . + P (A_{k}) P (B | A_{k})} \end{array}$

Here, j=1,...,k.

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