of 15 > Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4 HCl(aq) + MnO₂ (s) - MnCl₂ (aq) + 2 H₂O(1) + Cl₂(g) A sample of 39.9 g MnO, is added to a solution containing 44.5 g HCl. What is the limiting reactant? HCI MnO₂ What is the theoretical yield of Cl₂? theoretical yield: If the yield of the reaction is 86.1%, what is the actual yield of chlorine? 8 Cl₂
of 15 > Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4 HCl(aq) + MnO₂ (s) - MnCl₂ (aq) + 2 H₂O(1) + Cl₂(g) A sample of 39.9 g MnO, is added to a solution containing 44.5 g HCl. What is the limiting reactant? HCI MnO₂ What is the theoretical yield of Cl₂? theoretical yield: If the yield of the reaction is 86.1%, what is the actual yield of chlorine? 8 Cl₂
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide.
4 HCl(aq) + MnO₂ (s)→ MnCl₂ (aq) + 2 H₂O(1) + Cl₂(g)
A sample of 39.9 g MnO, is added to a solution containing 44.5 g HCI.
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What is the limiting reactant?
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What is the theoretical yield of Cl₂?
theoretical yield:
If the yield of the reaction is 86.1%, what is the actual yield of chlorine?
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Expert Solution
Step 1
Given,
4HCl(aq) + MnO2(s) → MnCl2(aq) + 2H2O(l) + Cl2(g)
mass of HCl react = 44.5 g
mass of MnO2 react = 39.9 g
a) Limiting reactant = ?
b) Theoretical yield of Cl2 = ?
c) Actual yield of chlorine (Cl2) = ?
Percent yield = 86.1 %
Note:
molar mass of HCl = 36.458 g/mol
molar mass of MnO2 = 87 g/mol
molar mass of Cl2 = 70.906 g/mol
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