16.792 g of Ba(OH)2 (171.342 g.mol) is weighed out and carefully dissolved to make a 500.00cm solution. A 25.00 cm³ of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(N03)2(aq) + 2H2O(1) The concentration of Ba(OH)2 in the 100.00 cm3 volumetric flask is: O 1.96 x 103 M O 5.21 x 103 M O 4.90 x 10-2M O 1.96 x 101 M O 3.92 x 103 M O None of the above
16.792 g of Ba(OH)2 (171.342 g.mol) is weighed out and carefully dissolved to make a 500.00cm solution. A 25.00 cm³ of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(N03)2(aq) + 2H2O(1) The concentration of Ba(OH)2 in the 100.00 cm3 volumetric flask is: O 1.96 x 103 M O 5.21 x 103 M O 4.90 x 10-2M O 1.96 x 101 M O 3.92 x 103 M O None of the above
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm solution. A 25.00 cm of this solution is pipette then transfer
into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3.
Ba(OH)2(aq) + 2HNO3(aq) → Ba(N03)2(aq) + 2H2O(1)
The concentration of Ba(OH)2 in the 100.00 cm3 volumetric flask is:
O 1.96 x 103 M
O 5.21 x 10-3 m
O 4.90 x 10 2M
O 1.96 x 101 M
O 3.92 x 103 M
O None of the above
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