What is the concentration of a solution iif 6.12 g of calcium sulfite (molar mass 120.2 amu) is added to a 100.0 mL volumetric flask and water added to the line?
What is the concentration of a solution iif 6.12 g of calcium sulfite (molar mass 120.2 amu) is added to a 100.0 mL volumetric flask and water added to the line?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Determining the Concentration of a Calcium Sulfite Solution
**Problem Statement:**
What is the concentration of a solution if 6.12 g of calcium sulfite (molar mass 120.2 amu) is added to a 100.0 mL volumetric flask and water is added to the line?
**Step-by-Step Solution:**
1. **Calculate the Number of Moles of Calcium Sulfite:**
\[
\text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}}
\]
\[
= \frac{6.12 \text{ g}}{120.2 \text{ g/mol}}
\]
\[
= 0.0509 \text{ mol}
\]
2. **Convert Volume from milliliters to liters:**
\[
100.0 \text{ mL} = 0.1000 \text{ L}
\]
3. **Calculate the Concentration (Molarity) of the Solution:**
\[
\text{Molarity (M)} = \frac{\text{Number of moles}}{\text{Volume in liters}}
\]
\[
= \frac{0.0509 \text{ mol}}{0.1000 \text{ L}}
\]
\[
= 0.509 \text{ M}
\]
**Conclusion:**
The concentration of the calcium sulfite solution is 0.509 M.
*Note: There are no accompanying graphs or diagrams with this problem.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff65fb7b2-ba85-4e67-8fe1-01f97a564d1e%2F268451a0-c8b7-4e71-93fc-27236f1fd341%2F0u4z68t_processed.png&w=3840&q=75)
Transcribed Image Text:### Determining the Concentration of a Calcium Sulfite Solution
**Problem Statement:**
What is the concentration of a solution if 6.12 g of calcium sulfite (molar mass 120.2 amu) is added to a 100.0 mL volumetric flask and water is added to the line?
**Step-by-Step Solution:**
1. **Calculate the Number of Moles of Calcium Sulfite:**
\[
\text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}}
\]
\[
= \frac{6.12 \text{ g}}{120.2 \text{ g/mol}}
\]
\[
= 0.0509 \text{ mol}
\]
2. **Convert Volume from milliliters to liters:**
\[
100.0 \text{ mL} = 0.1000 \text{ L}
\]
3. **Calculate the Concentration (Molarity) of the Solution:**
\[
\text{Molarity (M)} = \frac{\text{Number of moles}}{\text{Volume in liters}}
\]
\[
= \frac{0.0509 \text{ mol}}{0.1000 \text{ L}}
\]
\[
= 0.509 \text{ M}
\]
**Conclusion:**
The concentration of the calcium sulfite solution is 0.509 M.
*Note: There are no accompanying graphs or diagrams with this problem.*
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