What mass of precipitate (in g) is formed when 250.0 mL of 0.610 M CuCh is mixed with excess KOH in the following chemical reaction? CuCL(aq) + 2 KOH(aq)→Cu(OH)>(s) + 2 KCI(aq)

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**Chemical Reaction Problem on Precipitate Formation**

**Question:**  
What mass of precipitate (in g) is formed when 250.0 mL of 0.610 M CuCl₂ is mixed with excess KOH in the following chemical reaction?  

**Chemical Reaction:**  
CuCl₂(aq) + 2 KOH(aq) → Cu(OH)₂(s) + 2 KCl(aq)  

**Explanation:**  
This problem involves calculating the mass of a precipitate formed when copper(II) chloride (\( \text{CuCl}_2 \)) reacts with potassium hydroxide (\( \text{KOH} \)). The reaction yields copper(II) hydroxide (\( \text{Cu(OH)}_2 \)) as a solid precipitate and potassium chloride (\( \text{KCl} \)) in solution. The solution is prepared with an excess of KOH, ensuring the formation of the maximum amount of precipitate.
Transcribed Image Text:**Chemical Reaction Problem on Precipitate Formation** **Question:** What mass of precipitate (in g) is formed when 250.0 mL of 0.610 M CuCl₂ is mixed with excess KOH in the following chemical reaction? **Chemical Reaction:** CuCl₂(aq) + 2 KOH(aq) → Cu(OH)₂(s) + 2 KCl(aq) **Explanation:** This problem involves calculating the mass of a precipitate formed when copper(II) chloride (\( \text{CuCl}_2 \)) reacts with potassium hydroxide (\( \text{KOH} \)). The reaction yields copper(II) hydroxide (\( \text{Cu(OH)}_2 \)) as a solid precipitate and potassium chloride (\( \text{KCl} \)) in solution. The solution is prepared with an excess of KOH, ensuring the formation of the maximum amount of precipitate.
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