Solve for interface temperatures.Given: heat transfer due to radiation= 507.415 W/m2 o heatsource\- 140°CCiven:composite wall(3 layers)Pory unethaneboardcorere terock(15 cm,woolk>0.742(0.5 cm ,(0.38cm,WIm2 Kk=0.03 a2m²Kk=0.0397Tonue tew Im" K32°CCxposed toair andheat soureEmirr ivity0.90

given data- rate of heat transfer = 507.415 W/m2 concrete temperature = 32 degree C tconcrete= 15 cm…

Answered: O heat source 1나0°C Given: composite…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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Please solve both parts with handwriting please need with correct answer need awesome answer solve both handwriting i requested to u. Part6. An exposed 8 cm external diameter, 20 m long hot-water pipe at 80°C is losing heat to the surrounding (outdoor) air by natural convection. The average outdoor temperature is 5°C. The heat transfer coefficient is 25 W/m2°C. What is the heat loss by natural convection, in kW? A. 9.4 W B. 10.0 W C. 10.4 W D. 11.4 W Part7. A spherical ball with a diameter of 10 cm has an outer surface that is maintained at a temperature of 200°C. It is suspended in the middle of a room that has an average temperature of 20°C. If the surface emissivity is 0.8, determine the rate of radiative heat transfer from the ball to the room in W. (Choose the nearest value) A. 2.3 W B. 4.5 W C. 19.4 W D. 60.8 W
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A convection problem has a Nusselt number equai to 10. where the contribution of diffusion is normalised and set equal to a value of 1.0. Select the correct statementis): | The ratio of advection to diffusion is 9. The ratio advection to convection is 10 The ratio of convection to diffusion is 10. The ratio advection to convection is 9. The ratio of advection to diffusion is 10.
The wall of a furnace comprises three layers as shown in the figuie. The first layer is tery (whose maximum allowable temperature is 1400°C) while the second laver is Tracto:y Chose maximum allowable temperature is 1093°C). The third layer is a plate of 6 35 od thermal contact. Steet plare To 6.35x3 45A 1370 C Concerntiation veluciy 37.8 C mass Siynes Figure. Layers in a composite furnace wall. e temperature To on the inside of the refractory is 1370°C, while the temperature T; on the side of the steel plate is 37.8° The heat loss through the furnace HnIlisexpectet tobe
A hole is to be punched out on a layer of papers using a puncher with a hole diameter of 100 mm. If the compressive stress in the punch is limited to 15.1 Mpa. Calculate for the maximum stacking depth (mm) of paper for a single punch considering each paper is 125 micron and a shearing strength of 13.5 Mpa
Match the appropriate thermal conductivity walue for the given materials Material Thermal Conductivity (K) 4. Diamond 0.026 W/m K B. Copper 2. 0.607 W/m K c. Water 3. 385 Wm K D. Ar 2300 Wm K O a. A-I, B-IV, C-I, D-I O b. A-II, B-I C-I D-IV Oc A-IV, B-II, C-II, D-I O d. A-I, B-I, C-II D-IV
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Required information Sometimes equations can be developed and practical problems solved by knowing nothing more than the dimensions of the key parameters. For example, consider the heat loss through a window in a building. Window efficiency is rated in terms of R value, which has the unit of ft2-hr-°F/Btu. A certain manufacturer offers a double-pane window with R = 2.5 and also a triple-pane window with R= 3.4. Both windows are 3.5 ft by 5 ft. On a given winter day, the temperature difference between the inside and outside is 45°F. How much heat is lost through the double-pane window? 315 Btu Return to question
1- Microwave radiation is incident on one side of a planar wall with a heat conductivity coefficient k. (x=0) -D°b=(x)b leads to volumetric heating. While this surface is 9(W/m²) microwave radiation is fixed. kept at a constant temperature To, the other surface at x=L is very well insulated. Determine the temperature distribution T(x) in terms of x, L, k, qo and To.

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O heat source 1나0°C Given: composite wall (3 layers) poy unethane board Corerete rock wool (15 cm, k> 0.742 W/m? K (0.5 cm , (0.38cm, k= 0.0397 w Im" K k= 0.03 92 Tconue te 32°C Chposed to ain and heat souru Emisr witey * 0.90