Consider a thick cylindrical wall with insulation at both the inner and outer walls. The inner and outer radii of the thick cylinder are 1₂ = 40 cm and 13 = 80 cm, respectively. The length of cylinder is 1 meter. The thermal conductivity of the wall is k₂ = 120- W mk The thickness of outer insulation is 5 cm and its thermal conductivity is k3 = 12 The thickness of the inner insulation W mk W mk wall k2 = 120 W/mK . The heat r3=80 cm 2 = 40 cm is also 5 cm, but the thermal conductivity is k₁ = 8 dissipates through the surface of outer sides of the insulation W through convention with h, = 50 and the ambient m²K temperature outside the pipe is T = 25°C. The inner most surface is maintained at 80°C. Compute the heat transfer through the wall and the temperature of the outer most surface. Use resistance models to solve this problem. r1 = 35 cm r4 = 85 cm inner insulation k1 = 8 W/mK outer insulation k3 = 12 W/mK
Consider a thick cylindrical wall with insulation at both the inner and outer walls. The inner and outer radii of the thick cylinder are 1₂ = 40 cm and 13 = 80 cm, respectively. The length of cylinder is 1 meter. The thermal conductivity of the wall is k₂ = 120- W mk The thickness of outer insulation is 5 cm and its thermal conductivity is k3 = 12 The thickness of the inner insulation W mk W mk wall k2 = 120 W/mK . The heat r3=80 cm 2 = 40 cm is also 5 cm, but the thermal conductivity is k₁ = 8 dissipates through the surface of outer sides of the insulation W through convention with h, = 50 and the ambient m²K temperature outside the pipe is T = 25°C. The inner most surface is maintained at 80°C. Compute the heat transfer through the wall and the temperature of the outer most surface. Use resistance models to solve this problem. r1 = 35 cm r4 = 85 cm inner insulation k1 = 8 W/mK outer insulation k3 = 12 W/mK
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The first part of the question has been worked on, where the heat transfer was calculated to be 6.770 kilowatt, but the problem also asks to calculate the temperature of the outer most surface. What is the temperature of the outer most surface?

Transcribed Image Text:Consider a thick cylindrical wall with insulation at both the inner
and outer walls. The inner and outer radii of the thick cylinder are
12 = 40 cm and 13 = 80 cm, respectively. The length of cylinder
is 1 meter. The thermal conductivity of the wall is k₂ = 120-
The thickness of outer insulation is 5 cm and its thermal
conductivity is k3 = 12 . The thickness of the inner insulation
W
mk
W
mk
W
The heat
mk
=
is also 5 cm, but the thermal conductivity is k₁ = 8
dissipates through the surface of outer sides of the insulation
through convention with h, 50- and the ambient
temperature outside the pipe is T
surface is maintained at 80°C. Compute the heat transfer through the wall and the temperature of
the outer most surface.
W
m²K
= 25°C. The inner most
Use resistance models to solve this problem.
wall
k2 = 120 W/mK
r3= 80 cm
r2 = 40 cm
r1 = 35 cm
inner insulation
k1 = 8 W/mK
r4 = 85 cm
outer insulation
k3 = 12 W/mK

Transcribed Image Text:બબતો/
K₂= /20
1=350m = 0.35m
N₂ =
= 400m = 0.4mu
V3 = 80cm = 0.8m
Vy=85cm = 0.85m
1 W/mk
los (only sli)
82
luf
Inner
Insulation
K₁=8 W/mk
ry
к ты
www
Ti In (²4) In (13)
27 K₂L
2741
Total Resisterna
Rtotal = pthi + R+42 +R+h3 + Room
Rotol
In [/2) + In (141)
Dim tr₂/ +
27K11
27/24
Y3
27K3L
ho=
ambient temperature outside pipe Too = 2.5°C
Inner most surfde Tou perature Ti = 80°C
convection Heat transfer coefficient of outside surpree ho= 50w
m² k
Length of cylinder
= IM
RT42
kth 3
Heat dispitale through surfree
outer
Insulation
50 W
=
1²15
k3= 12W/mk
t
Rconv
mm Too
ㅗ
ho (27 XL)
1
10:45) + In (0:50) + In (0.65)
0.8
27x8x1
27 x (20x) 27X12X1
27 KL ho(2784L)
f.
Rolal = 2.6565X10 3 +9.193x10-4+8.04659 × 10 ++3.744x10-3
Rotol = 8.1238 X1b-3 k/w
Heat dissipates through surface
50x (27x 0.85X1,
(T₁ - Too) walt
R Total
(80-25)
8.1238 X103
= 6770.18 watt
-6.770 kilowatt
Ar
Expert Solution

Step 1
Given:
To find:
Outer surface temperature To
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