Now that the order for both reactants is known, the rate constant, k, can be determined. Each of the four trials can be used to calculate k and then the four results can be averaged. We will use Trial 4 to determine the rate constant in this example. What is the value of the rate constant? [A), mol/L (B), mol/L rate, mol/(L-min) Trial 1 0.931 0.549 0.0781 Trial 2 1.86 0.549 0.0781 Trial 3 0.931 1.10 0.312 Trial 4 0.466 0.829 0.178 Rate = k[4]°Le)? L/molemin

Now that the order for both reactants is known, the rate constant, k, can be determined. Each of the four trials can be used to calculate k and then the four results can be averaged. We will use Trial 4 to determine the rate constant in this example. What is the value of the rate constant? [A), mol/L (B), mol/L rate, mol/(L-min) Trial 1 0.931 0.549 0.0781 Trial 2 1.86 0.549 0.0781 Trial 3 0.931 1.10 0.312 Trial 4 0.466 0.829 0.178 Rate = k[4]°Le)? L/molemin

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Determine the overall rate law for the reaction CH3Br(aq) + OH (aq) → CH3OH(aq) + Br (aq). The data is given below Experiment [CH3B1] (M) [OH"] (M) Initial rate (M/s) k[CH3B1][OH¯]³ O k[CH3B1]°[OH73 1 0.12 0.12 5.2 x 10-5 O k[CH3B1]?[OH"7² 2 0.24 0.12 1.04 x 10-4 O k 3 0.12 0.06 6.5 x 10-6 O KỊCH3B1]°[OH"]) O k(CH3B1]?[OH"]
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A) Consider the following reaction: 4 Zn(s) + 10 H+ + 2 NO3- --> 4 Zn2+ + N2O(g) + 5 H2O(l) What is the rate law for this reaction? Group of answer choices rate = k [H+][NO3-] rate = k [H+]10[NO3-]2[Zn2+]4[N2O] More information is needed to determine this. rate = k [H+]10[NO3-]2 B) Consider the following reaction: 4 Zn(s) + 10 H+ + 2 NO3- --> 4 Zn2+ + N2O(g) + 5 H2O(l) If the rate of H+ disappearance is 0.0250 M/min, what is the rate of Zn2+ appearance? Group of answer choices 0.0100 M/min 0.00100 M/min 0.0250 M/min 0.0625 M/min
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Now that the order for both reactants is known, the rate constant, k, can be determined. Each of the four trials can be used to calculate k and then the four results can be averaged. We will use Trial 4 to determine the rate constant in this example. What is the value of the rate constant? [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.917 0.950 0.252 Trial 2 1.83 0.950 0.504 Trial 3 0.917 1.90 0.504 Trial 4 0.818 0.437 0.103 Rate = k[A]1[B]1
Ⓒ Macmillan Learning Enter these data into the graphing tool and determine the value and units of the rate constant, k, for this reaction. Graphing Tool Add Row 10 total rows [A] [A] vs. t In[A] In[A] vs. t t (min) 0.0 2.0 4.0 6.0 1/[A] vs. t [A] (M) 1.00 0.66 0.43 0.28 1/[A] Clear All Data
E. For the reaction A+B+C→D+EA+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A][A](MM) [B][B](MM) [C][C](MM) Initial rate(M/sM/s) 1 0.30 0.30 0.30 9.0×10−5 2 0.30 0.30 0.90 2.7×10−4 3 0.60 0.30 0.30 3.6×10−4 4 0.60 0.60 0.30 3.6×10−4
Use the following data table to answer the following questions. Experiment Concn. of A (M) Concn. of B (M) Initial rate (M/s) 1 0.10 0.010 1.2e-3 2 0.10 0.040 4.8e-3 3 0.20 0.010 2.4e-3 d. The rate constant of the reaction is e. The rate of reaction when concentration of A and B are 0.15M and 0.075M is
O KINETICS AND EQUILIBRIUM Using a second-order integrated rate law to find concentration... -1-1 At a certain temperature the rate of this reaction is second order in Cl,0, with a rate constant of 103.Ms: 2Cl,0; (g) 2Cl, (g) +50, (g) → Suppose a vessel contains Cl,0, at a concentration of 0.130M. Calculate the concentration of Cl,0, in the vessel 0.550 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. OM x10 Check Explanation Terms of Use | Privacy Center Accessibility 2021 McGraw Hill LLC. All Rights Reserved. II
O KINETICS AND EQUILIBRIUM 三 Deducing a rate law from the change in concentration over time A chemistry graduate student is studying the rate of this reaction: NH,OH (aq) → NH, (aq)+H,0 (aq) She fills a reaction vessel with NH,OH and measures its concentration as the reaction proceeds: time [NH,OH] (milliseconds) 0.500 M 10. 0.314 M 20. 0.197 M 30. 0.123 M 40. 0.0775 M Use this data to answer the following questions. Writo the rato lau fonr thir roation ato - O Explanation Check O 2021 McGraw-Hill Education. All Rights Reserved Terms Type here to search