Please explain to my why the rate is 1/3 when it takes two O3 molecules to produce three O2 molecules **The Rate of a Chemical Reaction**At a particular time in the reaction below, the concentration of O₂ increases from 0.0800 M to 0.0920 M in 10 seconds. What is the rate of the reaction during this time interval?\[ 2 \, \text{O}_3 \rightarrow 3 \, \text{O}_2 \]**Answer:** a) +0.00040 M/sThe rate of the reaction is calculated using the following formula:\[ \text{rate} = \frac{1}{3} \frac{\Delta [\text{O}_2]}{\Delta t} \]\[ = \frac{1}{3} \times \frac{(0.0920 \, \text{M} - 0.0800 \, \text{M})}{10 \, \text{s}} \]

Answered: At a particular time in the reaction…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Please explain to my why the rate is 1/3 when it takes two O3 molecules to produce three O2 molecules

**The Rate of a Chemical Reaction**

At a particular time in the reaction below, the concentration of O₂ increases from 0.0800 M to 0.0920 M in 10 seconds. What is the rate of the reaction during this time interval?

\[ 2 \, \text{O}_3 \rightarrow 3 \, \text{O}_2 \]

**Answer:** a) +0.00040 M/s

The rate of the reaction is calculated using the following formula:

\[ \text{rate} = \frac{1}{3} \frac{\Delta [\text{O}_2]}{\Delta t} \]

\[ = \frac{1}{3} \times \frac{(0.0920 \, \text{M} - 0.0800 \, \text{M})}{10 \, \text{s}} \]

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The rate of a chemical reaction is a measure of how quickly reactants are converted to products. It is typically expressed as the change in concentration of a reactant or product per unit time.

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