A student follows the Determining the Rate Law for the Crystal Violet-Hydroxide lon Reaction procedure. The stock concentration of sodium hydroxide used in trial 1 is 0.018 M. The stock concentration of sodium hydroxide used in trial 2 is 0.012 M. Given the data below, what is the hydroxide ion concentration (M) in the trial 2 reaction mixture? Give your answer to four decimal places. Trial 1 Trial 2 Volume NaOH (mL) 5.00 5.00 Volume Crystal Violet (mL) 5.00 5.00

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A student follows the Determining the Rate Law for the Crystal Violet-Hydroxide lon
Reaction procedure. The stock concentration of sodium hydroxide used in trial 1 is
0.018 M. The stock concentration of sodium hydroxide used in trial 2 is 0.012 M.
Given the data below, what is the hydroxide ion concentration (M) in the trial 2
reaction mixture? Give your answer to four decimal places.
Trial 1
Trial 2
Volume NaOH
(mL)
5.00
5.00
Volume Crystal Violet
(mL)
5.00
5.00
Transcribed Image Text:A student follows the Determining the Rate Law for the Crystal Violet-Hydroxide lon Reaction procedure. The stock concentration of sodium hydroxide used in trial 1 is 0.018 M. The stock concentration of sodium hydroxide used in trial 2 is 0.012 M. Given the data below, what is the hydroxide ion concentration (M) in the trial 2 reaction mixture? Give your answer to four decimal places. Trial 1 Trial 2 Volume NaOH (mL) 5.00 5.00 Volume Crystal Violet (mL) 5.00 5.00
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