Now Jed and Kadia tackle a homework problem: An object of mass m, = 13 kg and velocity v, 5.5 m/s crashes into another object of mass m, = 6 kg and %3D velocity v2 forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies. = -20.5 m/s. The two particles stick together as a result of the collision. Because no external m V1+ m2V2i = (m, + m2)Vf If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.)..
Now Jed and Kadia tackle a homework problem: An object of mass m, = 13 kg and velocity v, 5.5 m/s crashes into another object of mass m, = 6 kg and %3D velocity v2 forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies. = -20.5 m/s. The two particles stick together as a result of the collision. Because no external m V1+ m2V2i = (m, + m2)Vf If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.)..
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Educational Content Transcription:**
**Jed is correct. The mechanical energy (kinetic + potential) is not conserved, but the total energy is.**
---
**Part 9 of 10 - Analyze**
Now Jed and Kadia tackle a homework problem:
An object of mass \( m_1 = 13 \, \text{kg} \) and velocity \( v_1 = 5.5 \, \text{m/s} \) crashes into another object of mass \( m_2 = 6 \, \text{kg} \) and velocity \( v_2 = -20.5 \, \text{m/s} \). The two particles stick together as a result of the collision. Because no external forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies.
\[ m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \]
If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.)
**Input Box:**
"Enter a number. you submitted has the wrong sign." *unit: m/s*
**Buttons:**
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Transcribed Image Text:**Educational Content Transcription:**
**Jed is correct. The mechanical energy (kinetic + potential) is not conserved, but the total energy is.**
---
**Part 9 of 10 - Analyze**
Now Jed and Kadia tackle a homework problem:
An object of mass \( m_1 = 13 \, \text{kg} \) and velocity \( v_1 = 5.5 \, \text{m/s} \) crashes into another object of mass \( m_2 = 6 \, \text{kg} \) and velocity \( v_2 = -20.5 \, \text{m/s} \). The two particles stick together as a result of the collision. Because no external forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies.
\[ m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \]
If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.)
**Input Box:**
"Enter a number. you submitted has the wrong sign." *unit: m/s*
**Buttons:**
[Submit] [Skip (you cannot come back)]
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