- A horizontal force is applied to a 4.0 kg box. The box starts from rest moves a horizont- 20 meters and obtains a velocity of 6.0 m/s. The system is frictionless. O Find the change in kinetic energy. k=1/2mv² 0 to J O Find the work done by the horizontal force. =Fdcos W=8- of Find the horizontal force. Famion (th) .A 5.0 kg block moves in a straight line on a horizontal ictionless surface under the influence of a force that aries with position. Calculate the amount of work done by he force as the block moves from the origin to x = 8.0 m. 10 5 0 -5 -10 Force (N) 0 2

College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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3. B and C
of kings inition
3. A horizontal force is applied to a 4.0 kg box. The box starts from rest moves a horizontal distance of
8.0 meters and obtains a velocity of 6.0 m/s. The system is frictionless.
a) Find the change in kinetic energy.
k=½ mv ²
22.4.6²
0 to
72J
b) Find the work done by the horizontal force.
W=Fdcos
W=8.
c) Find the horizontal force.
before it hits the
4. A 5.0 kg block moves in a straight line on a horizontal
frictionless surface under the influence of a force that
varies with position. Calculate the amount of work done by
the force as the block moves from the origin to x = 8.0 m.
10
5
0
-5
-10
0
Force (N)
2
4
6
→Position (m)
Transcribed Image Text:of kings inition 3. A horizontal force is applied to a 4.0 kg box. The box starts from rest moves a horizontal distance of 8.0 meters and obtains a velocity of 6.0 m/s. The system is frictionless. a) Find the change in kinetic energy. k=½ mv ² 22.4.6² 0 to 72J b) Find the work done by the horizontal force. W=Fdcos W=8. c) Find the horizontal force. before it hits the 4. A 5.0 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with position. Calculate the amount of work done by the force as the block moves from the origin to x = 8.0 m. 10 5 0 -5 -10 0 Force (N) 2 4 6 →Position (m)
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