Physics **Projectile Motion Problem:**A 44.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 144 m/s from the top of a cliff 152 m above level ground, where the ground is considered to be \( y = 0 \).---**(a)** *What is the initial total mechanical energy of the projectile?*- (Provide your answer to at least three significant figures.)Calculated Answer: \( 5.217 \times 10^5 \, \text{J} \) ✓---**(b)** *Suppose the projectile is traveling 102.1 m/s at its maximum height of \( y = 368 \, \text{m} \). How much work has been done on the projectile by air friction?*Calculated Answer: \( -1.33 \times 10^5 \, \text{J} \) ✓---**(c)** *What is the speed of the projectile immediately before it hits the ground if air friction does one and a half times as much work on the projectile when it is going down as it did when it was going up?*Initial Calculated Answer: \( 90.1 \, \text{m/s} \) ✗- *Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.* \(\text{m/s}\)---**Need Help?**Click "Read It" for additional guidance.[Submit Answer]

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A 44.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 144 m/s from the top of a cliff 152 m above level ground, where the ground is taken to be y 0. (a) What is the initial total mechanical energy of the projectile? (Give your answer to at least three significant figures.) 5.217e+05 (b) Suppose the projectile is traveling 102.1 m/s at its maximum height of y = 368 m. How much work has been done on the projectile by air friction? -1.33e+05 (c) What is the speed of the projectile immediately before it hits the ground if air friction does one and a half times as much work on the projectile when it is going down as it did when it was going up? 90.1

A 44.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 144 m/s from the top of a cliff 152 m above level ground, where the ground is taken to be y 0. (a) What is the initial total mechanical energy of the projectile? (Give your answer to at least three significant figures.) 5.217e+05 (b) Suppose the projectile is traveling 102.1 m/s at its maximum height of y = 368 m. How much work has been done on the projectile by air friction? -1.33e+05 (c) What is the speed of the projectile immediately before it hits the ground if air friction does one and a half times as much work on the projectile when it is going down as it did when it was going up? 90.1

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Physics

**Projectile Motion Problem:**

A 44.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 144 m/s from the top of a cliff 152 m above level ground, where the ground is considered to be \( y = 0 \).

---

**(a)** *What is the initial total mechanical energy of the projectile?*
- (Provide your answer to at least three significant figures.)

Calculated Answer: \( 5.217 \times 10^5 \, \text{J} \) ✓

---

**(b)** *Suppose the projectile is traveling 102.1 m/s at its maximum height of \( y = 368 \, \text{m} \). How much work has been done on the projectile by air friction?*

Calculated Answer: \( -1.33 \times 10^5 \, \text{J} \) ✓

---

**(c)** *What is the speed of the projectile immediately before it hits the ground if air friction does one and a half times as much work on the projectile when it is going down as it did when it was going up?*

Initial Calculated Answer: \( 90.1 \, \text{m/s} \) ✗

- *Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.* \(\text{m/s}\)

---

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