U B mercury h₂ 1 of 1 Use these rules to work out the following problem: A U-shaped tube is connected to a box at one end and open to the air at the other end. The box is full of gas at pressure pgas, and the tube is filled with mercury of density 1.36x104 kg/m³. When the liquid in the tube reaches static equilibrium, the mercury column is h₁ 13.0 cm high in the left arm and h₂ = 6.00 cm high in the right arm, as shown in the figure.( Figure 1) What is the gas pressure Pgas inside the box? ▶ ▶ Part A Part B Part C Assume Patm = 1.00 atm. What is the gas pressure Pgas? Express your answer in pascals to three significant figures. View Available Hint(s) 15. ΑΣΦ Pgas 9.60 104 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Provide Feedback ? Pa C Next >

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Figure
Pgas
U
hy
BA
11₂
Y
mercury
1 of 1
>
TI-84 Plus CE
For a surface covered by a gas, po
Pgas
•
For a closed surface, p=F/A, where F is the force the surface, su
piston, exerts on the fluid and A is the area of the surface.
3. Use horizontal lines. Pressure in a connected fluid is the same at any point al
horizontal line.
4. Allow for gauge pressure. Pressure gauges read pg = p-1 atm.
5. Use the hydrostatic pressure equation: p = po + pgh, where p is the densit
is the free-fall acceleration, and h is the height of the fluid.
Use these rules to work out the following problem: A U-shaped tube is connected to a box at one end and
open to the air at the other end. The box is full of gas at pressure Pgas, and the tube is filled with mercury
of density 1.36x104 kg/m³. When the liquid in the tube reaches static equilibrium, the mercury column is
h₁ = 13.0 cm high in the left arm and h₂ = 6.00 cm high in the right arm, as shown in the figure.(
Figure 1) What is the gas pressure Pgas inside the box?
▶
Part A
▸ Part B
Part C
Assume Patm = 1.00 atm. What is the gas pressure Pgas ?
Express your answer in pascals to three significant figures.
► View Available Hint(s)
Pgas =
Submit
VE
9.60
Provide Feedback
●
ΑΣΦ
104
Previous Answers
Pay
X Incorrect; Try Again; 4 attempts remaining
?
Pa
Next >
Transcribed Image Text:Figure Pgas U hy BA 11₂ Y mercury 1 of 1 > TI-84 Plus CE For a surface covered by a gas, po Pgas • For a closed surface, p=F/A, where F is the force the surface, su piston, exerts on the fluid and A is the area of the surface. 3. Use horizontal lines. Pressure in a connected fluid is the same at any point al horizontal line. 4. Allow for gauge pressure. Pressure gauges read pg = p-1 atm. 5. Use the hydrostatic pressure equation: p = po + pgh, where p is the densit is the free-fall acceleration, and h is the height of the fluid. Use these rules to work out the following problem: A U-shaped tube is connected to a box at one end and open to the air at the other end. The box is full of gas at pressure Pgas, and the tube is filled with mercury of density 1.36x104 kg/m³. When the liquid in the tube reaches static equilibrium, the mercury column is h₁ = 13.0 cm high in the left arm and h₂ = 6.00 cm high in the right arm, as shown in the figure.( Figure 1) What is the gas pressure Pgas inside the box? ▶ Part A ▸ Part B Part C Assume Patm = 1.00 atm. What is the gas pressure Pgas ? Express your answer in pascals to three significant figures. ► View Available Hint(s) Pgas = Submit VE 9.60 Provide Feedback ● ΑΣΦ 104 Previous Answers Pay X Incorrect; Try Again; 4 attempts remaining ? Pa Next >
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