Answered: Nobel Laureate Richard Feynman once… | bartleby

Related questions

Question

Nobel Laureate Richard Feynman once said that if two persons stood at arm's length from each other and each person had 1% more electron than protons, the force of repulsion between them would be enough to lift a weight equal to that of the entire Earth. Carry out an order of magnitude calculations to substantiate this assertion. (you yourself suppose mass of each person)

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

and F represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of F/F is of the order of e (a) 1042 (c) 1024 (b) 10-²1 F g (d) 10-43 KAL
Considering electron and proton as two charged particles separated by d = 4.5 x 10m calculate the gravitational force between the proton and electron and find its ratio to the Coulomb force. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-³1 kg, the value of 1 the universal gravitational constant 6.7 × 10-¹1 N kg-2m-2, the electron charge -1.6 × 10- C and = 9 x 10⁹ m/F. Give the answer for Απερ the gravitational force in 10-47 N. 19
Say you have a point charge of one Coulomb and a hydrogen atom some distance away. Within what distance would the difference of forces on the proton and electron from the Coulomb charge exceed the attraction between the proton and electron that holds the hydrogen atom together. Treat the hydrogen atom as a proton and electron 0.53 × 10−10 m (a.k.a., one Bohr radius) apart.
An electron has a force of 4,8 x 10^16 N (towards the left) of an electric field. What is the correct answer for the electric field:a) 1,6 x 10^3 N/C (droite) b) 3,3 x 10^-4 N/C (droite) c) 3 x 10^3 N/C (droite) d) 2 x 10^3 N/C
A point charge for which Q = 5x10-16 C and m = 2 × 10-26 kg is moving in the combined fields E = 100ax – 300ay + 200az V/m and B = -ax + 2ay – 3az mT. If the charge velocity at t = 0 is v(0) = (4ax – 3ay - 2az)10³ m/s (a) give the unit vector showing the direction in which the charge is accelerating at t = 0; (b) using the electric field intensity what is the force at t=0, (c) using magnetic flux density what force is produce at t = 0. %3D
A hydrogen atom is located close to the surfsce of the earth. a) What is the ratio of the magnitude of the electric force between the electron and proton compared to the magnitude of the gravitational attraction between the electron and proton compared to the magnitude of the gravitational attraction between the electron and the earth? (This is how many times greater the electric force is in this situation) b) Draw a conclusion about the stability of matter. (How come gravity doesn't pull molecules apart?) c) Why is the gravitational force between the Earth and Moon greater than the electric force? (Since all matter is made of protons and electrons, why isn't electric force always greater?)
The three charge configurations are shown in the figure. For the values of q1=3.5uC, q2=-3.5 MC and q3=5 uC. The Forces of the three charges is calculated at q3. (Note:u=micro= 10^-6, If q3 has the mass of 10 grams, what will be the initial acceleration of q3 in m/s^2, due to q1 and q2?
The electric force between two charges, 4.1*10^-6C and 7.9*10^-6C, has a magnitude of 0.12N. What is the separation(r) between the charges?