Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron would the proton have to be? (k = 1/4TE0 = 9.0 x 10° N m2/C2, e = 1.6 x 10 19 C, %3D mproton = 1.67 × 1027 kg, melectron = 9.11 x 10-31 kg) 5.1 m 3.7 m 1.5 m 2.3 m 4.6 m

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Chapter1: Units, Trigonometry. And Vectors
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Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed
proton some distance above it. How far above the electron would the proton have to be?
(k = 1/4nE0 = 9.0 x 10° N m2/C2 , e = 1.6 x 10-19 C,
%3D
mproton = 1.67 × 102 kg, melectron
9.11 x 10
-31
kg)
5.1 m
3.7 m
1.5 m
2.3 m
4.6 m
Transcribed Image Text:Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron would the proton have to be? (k = 1/4nE0 = 9.0 x 10° N m2/C2 , e = 1.6 x 10-19 C, %3D mproton = 1.67 × 102 kg, melectron 9.11 x 10 -31 kg) 5.1 m 3.7 m 1.5 m 2.3 m 4.6 m
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