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P 35% Electron 9.18 x 107 T. out of the page 1.53 x 10-3 T, out of the page ○ 1.60 x 10-8 T, into the page 2.18 x 10-3 T, out of the page O 1.31 x 10-8 T, into the page O 1.53 x 10-³ T, into the page 9.18 x 10-9 T. into the page 2.18 x 10-3 T, into the page 1.60 x 10-8 T, out of the page 1.31 x 10-8 T, out of the page X An electron moves at 3.60 x 107 m/s as shown in the figure. Find the magnitude and direction of the magnetic field this electron produces at point P which is 6.00 um away from the electron. (e = 1.60 x 10-¹⁹ C)

P 35% Electron 9.18 x 107 T. out of the page 1.53 x 10-3 T, out of the page ○ 1.60 x 10-8 T, into the page 2.18 x 10-3 T, out of the page O 1.31 x 10-8 T, into the page O 1.53 x 10-³ T, into the page 9.18 x 10-9 T. into the page 2.18 x 10-3 T, into the page 1.60 x 10-8 T, out of the page 1.31 x 10-8 T, out of the page X An electron moves at 3.60 x 107 m/s as shown in the figure. Find the magnitude and direction of the magnetic field this electron produces at point P which is 6.00 um away from the electron. (e = 1.60 x 10-¹⁹ C)

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**Educational Content: Magnetic Field of a Moving Electron** **Diagram Explanation:** The diagram shows an electron moving with a velocity \( \vec{v} \) at \( 3.60 \times 10^7 \, \text{m/s} \). The electron is moving in the negative y-direction. The coordinate axes are labeled as \( x \) and \( y \), with the electron positioned at the origin. There's a point \( P \) located 6.00 micrometers away from the electron at a 35-degree angle below the x-axis. **Problem Statement:** An electron moves at \( 3.60 \times 10^7 \, \text{m/s} \) as shown in the figure. Find the magnitude and direction of the magnetic field this electron produces at point \( P \), which is \( 6.00 \, \mu \text{m} \) away from the electron. \((e = 1.60 \times 10^{-19} \, \text{C})\). **Answer Options:** - \( \circ \) \( 9.18 \times 10^{-9} \, \text{T, out of the page} \) - \( \circ \) \( 1.53 \times 10^{-3} \, \text{T, out of the page} \) - \( \circ \) \( 1.60 \times 10^{-8} \, \text{T, into the page} \) - \( \circ \) \( 2.18 \times 10^{-3} \, \text{T, out of the page} \) - \( \circ \) \( 1.31 \times 10^{-8} \, \text{T, into the page} \) - \( \circ \) \( 1.53 \times 10^{-3} \, \text{T, into the page} \) - \( \circ \) \( 9.18 \times 10^{-9} \, \text{T, into the page} \) - \( \circ \) \( 2.18 \times 10^{-3} \, \text{T, into the page} \) - \( \circ \) \( 1.60 \times 10^{-8} \, \text{T,
Transcribed Image Text:**Educational Content: Magnetic Field of a Moving Electron** **Diagram Explanation:** The diagram shows an electron moving with a velocity \( \vec{v} \) at \( 3.60 \times 10^7 \, \text{m/s} \). The electron is moving in the negative y-direction. The coordinate axes are labeled as \( x \) and \( y \), with the electron positioned at the origin. There's a point \( P \) located 6.00 micrometers away from the electron at a 35-degree angle below the x-axis. **Problem Statement:** An electron moves at \( 3.60 \times 10^7 \, \text{m/s} \) as shown in the figure. Find the magnitude and direction of the magnetic field this electron produces at point \( P \), which is \( 6.00 \, \mu \text{m} \) away from the electron. \((e = 1.60 \times 10^{-19} \, \text{C})\). **Answer Options:** - \( \circ \) \( 9.18 \times 10^{-9} \, \text{T, out of the page} \) - \( \circ \) \( 1.53 \times 10^{-3} \, \text{T, out of the page} \) - \( \circ \) \( 1.60 \times 10^{-8} \, \text{T, into the page} \) - \( \circ \) \( 2.18 \times 10^{-3} \, \text{T, out of the page} \) - \( \circ \) \( 1.31 \times 10^{-8} \, \text{T, into the page} \) - \( \circ \) \( 1.53 \times 10^{-3} \, \text{T, into the page} \) - \( \circ \) \( 9.18 \times 10^{-9} \, \text{T, into the page} \) - \( \circ \) \( 2.18 \times 10^{-3} \, \text{T, into the page} \) - \( \circ \) \( 1.60 \times 10^{-8} \, \text{T,
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