An electron revolve round the nucleus with the radius of the circular orbit is 'r'. To double the kinetic energy of the electron its orbital radius will be. v/ /2 (b) V2r, (a) (C) 2r (d) r/2
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- If the speed of the electron in Example 19-4 were 7.3 * 105m>s,what would be the corresponding orbital radius?A particle of ionizing radiation creates 4400 ion pairs in the gas inside a Geiger tube as it passes through. What minimum energy (in ev) was deposited, if 40.0 eV is required to create each ion pair? eV Additional MaterialsTwo electrons in the nucleus of a 238U atom are separated by a distance of 8 fm. What is the potential energy of the arrangement? A) 179.77 keVB) 2.25×10 43 eVC) 4.61×10 −33 keVD) 3.596 eV
- 3. A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. Dur- ing the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the col- lision there are two atoms: an atom of "heavy hydro- gen" (deuterium, m = 2.014 u) and an atom of oxygen-15 15.003 u). The incident helium atoms are moving at (m a velocity of 6.346 × 10° m/s. After the collision, the deu- terium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 10' m/s. (a) What is the final velocity of the oxygen-15 atoms? (b) Compare the total kinetic energies before and after the collision.In hydrogen atom an electron revolves around a nucleus in an orbit of radius 0.053 nm . If the frequency of revolution of electron is 6.6×10^15 Hz. Find the magnetic moment of the orbiting electron.4. In a hydrogen atom, the electron makes ω = 6×1015 rev/s (recall that this is the angular velocity) around the nucleus. We want to calculate how much current flows through a point in the orbit. (a) Calculate the time period of the orbit. Start by converting ω into rad/s. (b) Use the definition of current to calculate I due to the revolution of the electron around the nucleus.
- Question e(ii) and (iii)When a bound electron moves to location further from the nucleus, which of the following are true? energy of electron increases because it takes energy input to separate positive and negative charges, and there is a decrease in the electrostatic potential energy of the electron energy of electron increases because it takes energy input to separate positive and negative charges, and there is an increase in the electrostatic potential energy of the electron energy of electron decreases because energy is released as positive and negative charges are separated, and there is a decrease in electrostatic potential energy of electron since it is now further away7) (a) Figure 4 below shows how the potential, U, between two neutral atoms varies with their distance apart.