N Calculating equilibrium composition Suppose a 250. mL flask is filled with 1.8 mol of H₂ and 0.40 mol of HI. The following reaction becomes possible: H₂(g) +1₂(g) → 2HI(g) The equilibrium constant K for this reaction is 2.75 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places. M X Ś
N Calculating equilibrium composition Suppose a 250. mL flask is filled with 1.8 mol of H₂ and 0.40 mol of HI. The following reaction becomes possible: H₂(g) +1₂(g) → 2HI(g) The equilibrium constant K for this reaction is 2.75 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places. M X Ś
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Kinetics and Equilibrium: Calculating Equilibrium Composition from an Equilibrium Constant**
Suppose a 250 mL flask is filled with 1.8 mol of \( \text{H}_2 \) and 0.40 mol of HI. The following reaction becomes possible:
\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]
The equilibrium constant \( K \) for this reaction is 2.75 at the temperature of the flask.
Calculate the equilibrium molarity of HI. Round your answer to two decimal places.
[Input Box for Molarity Calculation]
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Transcribed Image Text:**Kinetics and Equilibrium: Calculating Equilibrium Composition from an Equilibrium Constant**
Suppose a 250 mL flask is filled with 1.8 mol of \( \text{H}_2 \) and 0.40 mol of HI. The following reaction becomes possible:
\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]
The equilibrium constant \( K \) for this reaction is 2.75 at the temperature of the flask.
Calculate the equilibrium molarity of HI. Round your answer to two decimal places.
[Input Box for Molarity Calculation]
There are no graphs or diagrams present in the image.
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