A chemist dissolves 852. mg of pure barium hydroxide in enough water to make up 160. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits. x10 Suppose a 500. mL flask is filled with 1.6 mol of NO2 and 0.60 mol of NO. This reaction becomes possible: 2NO2(g)=2NO(g) + O2(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O2. You can leave out the M symbol for molarity. NO2 NO 02 initial change equilibrium ☐ ☐ X ☐ ☑

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A chemist dissolves 852. mg of pure barium hydroxide in enough water to make up 160. mL of solution. Calculate the pH of the solution. (The temperature of
the solution is 25 °C.)
Be sure your answer has the correct number of significant digits.
x10
Transcribed Image Text:A chemist dissolves 852. mg of pure barium hydroxide in enough water to make up 160. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits. x10
Suppose a 500. mL flask is filled with 1.6 mol of NO2 and 0.60 mol of NO. This reaction becomes possible:
2NO2(g)=2NO(g) + O2(g)
Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the
equilibrium molarity of each compound after the reaction has come to equilibrium.
Use x to stand for the unknown change in the molarity of O2. You can leave out the M symbol for molarity.
NO2
NO
02
initial
change
equilibrium
☐
☐
X
☐
☑
Transcribed Image Text:Suppose a 500. mL flask is filled with 1.6 mol of NO2 and 0.60 mol of NO. This reaction becomes possible: 2NO2(g)=2NO(g) + O2(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O2. You can leave out the M symbol for molarity. NO2 NO 02 initial change equilibrium ☐ ☐ X ☐ ☑
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