Moles S2082- 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 Aliquot Solution 1 Time (t in secs) Moles of S2082- Solution 2 Solution 3 Time (t in secs) Moles of S2082- Time (t in secs) Moles of S2082- 141 0.0002 74 0.0002 100 0.0002 2 341 0.0004 155 0.0004 204 0.0004 3 555 0.0006 235 0.0006 272 0.0006 4 796 0.0008 321 0.0008 366 0.0008 5 1010 0.001 414 0.001 472 0.001 6 1259 0.0012 504 0.0012 548 0.0012 7 1524 0.0014 590 0.0014 669 0.0014 Solution 1 Rates of Chemical Reactions 0 0 200 400 600 800 y = 1E-06x R² = 0.9964 1000 1200 1400 1600 1800 Time (Seconds) Moles S2082- Solution 2 Rates of Chemical Reactions Solution 3 Rates of Chemical Reactions 0.0016 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 0.0014 0.0012 y = 2E-06x R² = 0.9993 Moles S2082- 0.001 0.0008 0.0006 0.0004 y=2E-06x R² = 0.9993 0.0002 0 0 0 100 200 300 400 500 600 700 0 100 200 300 400 500 600 700 800 Time (Seconds) Time (Seconds) RESULTS AND DATA: 1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR EACH IF YOU KNOW HOW TO. MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS) 2. MAKE A BEST FUT LINE MOLES S2082. *MAKE A SCATTEPLOT - ADD TRENDLINE - ADD EQUATION OF LINE - SET INTERCEPT TO '0' TIME (SECONDS) CALCULATING THE RATE OF EACH SOLUTION: USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES st NOW CALCULATE THE RATE SLOPE 0-100L TUTAL VOLUME FOR EACH Sohutzon * REMEMBER RATE = A[1 st SOLUTION MAKE A DATA TABLE SIMILAR TO PAGE 80: [52002-] [1-] RATE (M/S) 1 0.05M 0.05 M 2 0.10 M 0.05M 3 0.0511 0.107 4 0.10 M 0.0257 NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y RATS =K [3400 *] [I¯]* [52082-] USE SOLUTIONS 2 AND 1 RATE 2 RATE [S₂002-], M (0·10H) x 0.050 M x = x [1] USE SOLUTIONS 3 AND I RATE 3 = [I]3 OR Q AND 4 RATE [] y = 29 USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION RATE = k [S2002-] [1-]" * All CALCULATIONS MUST BE INCLUDED IN LAB REPORT
Moles S2082- 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 Aliquot Solution 1 Time (t in secs) Moles of S2082- Solution 2 Solution 3 Time (t in secs) Moles of S2082- Time (t in secs) Moles of S2082- 141 0.0002 74 0.0002 100 0.0002 2 341 0.0004 155 0.0004 204 0.0004 3 555 0.0006 235 0.0006 272 0.0006 4 796 0.0008 321 0.0008 366 0.0008 5 1010 0.001 414 0.001 472 0.001 6 1259 0.0012 504 0.0012 548 0.0012 7 1524 0.0014 590 0.0014 669 0.0014 Solution 1 Rates of Chemical Reactions 0 0 200 400 600 800 y = 1E-06x R² = 0.9964 1000 1200 1400 1600 1800 Time (Seconds) Moles S2082- Solution 2 Rates of Chemical Reactions Solution 3 Rates of Chemical Reactions 0.0016 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 0.0014 0.0012 y = 2E-06x R² = 0.9993 Moles S2082- 0.001 0.0008 0.0006 0.0004 y=2E-06x R² = 0.9993 0.0002 0 0 0 100 200 300 400 500 600 700 0 100 200 300 400 500 600 700 800 Time (Seconds) Time (Seconds) RESULTS AND DATA: 1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR EACH IF YOU KNOW HOW TO. MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS) 2. MAKE A BEST FUT LINE MOLES S2082. *MAKE A SCATTEPLOT - ADD TRENDLINE - ADD EQUATION OF LINE - SET INTERCEPT TO '0' TIME (SECONDS) CALCULATING THE RATE OF EACH SOLUTION: USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES st NOW CALCULATE THE RATE SLOPE 0-100L TUTAL VOLUME FOR EACH Sohutzon * REMEMBER RATE = A[1 st SOLUTION MAKE A DATA TABLE SIMILAR TO PAGE 80: [52002-] [1-] RATE (M/S) 1 0.05M 0.05 M 2 0.10 M 0.05M 3 0.0511 0.107 4 0.10 M 0.0257 NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y RATS =K [3400 *] [I¯]* [52082-] USE SOLUTIONS 2 AND 1 RATE 2 RATE [S₂002-], M (0·10H) x 0.050 M x = x [1] USE SOLUTIONS 3 AND I RATE 3 = [I]3 OR Q AND 4 RATE [] y = 29 USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION RATE = k [S2002-] [1-]" * All CALCULATIONS MUST BE INCLUDED IN LAB REPORT
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
Section: Chapter Questions
Problem 6.21P: 6-21 Are mixtures of gases true solutions or heterogeneous mixtures? Explain.
Related questions
Question
Transcribed Image Text:Moles S2082-
0.0016
0.0014
0.0012
0.001
0.0008
0.0006
0.0004
0.0002
Aliquot
Solution 1
Time (t in secs) Moles of S2082-
Solution 2
Solution 3
Time (t in secs) Moles of S2082-
Time (t in secs) Moles of S2082-
141
0.0002
74
0.0002
100
0.0002
2
341
0.0004
155
0.0004
204
0.0004
3
555
0.0006
235
0.0006
272
0.0006
4
796
0.0008
321
0.0008
366
0.0008
5
1010
0.001
414
0.001
472
0.001
6
1259
0.0012
504
0.0012
548
0.0012
7
1524
0.0014
590
0.0014
669
0.0014
Solution 1
Rates of Chemical Reactions
0
0
200
400
600
800
y = 1E-06x
R² = 0.9964
1000 1200 1400 1600 1800
Time (Seconds)
Moles S2082-
Solution 2
Rates of Chemical Reactions
Solution 3
Rates of Chemical Reactions
0.0016
0.0016
0.0014
0.0012
0.001
0.0008
0.0006
0.0004
0.0002
0.0014
0.0012
y = 2E-06x
R² = 0.9993
Moles S2082-
0.001
0.0008
0.0006
0.0004
y=2E-06x
R² = 0.9993
0.0002
0
0
0
100
200
300
400
500
600
700
0
100
200
300
400
500
600
700
800
Time (Seconds)
Time (Seconds)
![RESULTS AND DATA:
1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR
EACH IF YOU KNOW HOW TO.
MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS)
2. MAKE A BEST FUT LINE
MOLES S2082.
*MAKE A SCATTEPLOT
- ADD TRENDLINE
- ADD EQUATION OF LINE
- SET INTERCEPT TO '0'
TIME (SECONDS)
CALCULATING THE RATE OF EACH SOLUTION:
USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES
st
NOW CALCULATE THE RATE
SLOPE
0-100L
TUTAL VOLUME
FOR EACH Sohutzon
* REMEMBER
RATE = A[1
st
SOLUTION
MAKE A DATA TABLE SIMILAR TO PAGE 80:
[52002-]
[1-]
RATE (M/S)
1
0.05M
0.05 M
2
0.10 M
0.05M
3
0.0511
0.107
4
0.10 M
0.0257
NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y
RATS =K [3400 *] [I¯]*
[52082-]
USE SOLUTIONS
2 AND 1
RATE 2
RATE
[S₂002-],
M
(0·10H) x
0.050 M
x
=
x
[1] USE SOLUTIONS 3 AND I
RATE 3 = [I]3
OR
Q AND 4
RATE
[]
y
= 29
USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION
RATE = k [S2002-] [1-]"
* All CALCULATIONS MUST BE INCLUDED IN LAB REPORT](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd3497266-ffb8-4c22-a39d-6133d2c29024%2F8794b717-019f-47bd-8dcc-ee14494e00e6%2F0kzcco_processed.png&w=3840&q=75)
Transcribed Image Text:RESULTS AND DATA:
1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR
EACH IF YOU KNOW HOW TO.
MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS)
2. MAKE A BEST FUT LINE
MOLES S2082.
*MAKE A SCATTEPLOT
- ADD TRENDLINE
- ADD EQUATION OF LINE
- SET INTERCEPT TO '0'
TIME (SECONDS)
CALCULATING THE RATE OF EACH SOLUTION:
USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES
st
NOW CALCULATE THE RATE
SLOPE
0-100L
TUTAL VOLUME
FOR EACH Sohutzon
* REMEMBER
RATE = A[1
st
SOLUTION
MAKE A DATA TABLE SIMILAR TO PAGE 80:
[52002-]
[1-]
RATE (M/S)
1
0.05M
0.05 M
2
0.10 M
0.05M
3
0.0511
0.107
4
0.10 M
0.0257
NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y
RATS =K [3400 *] [I¯]*
[52082-]
USE SOLUTIONS
2 AND 1
RATE 2
RATE
[S₂002-],
M
(0·10H) x
0.050 M
x
=
x
[1] USE SOLUTIONS 3 AND I
RATE 3 = [I]3
OR
Q AND 4
RATE
[]
y
= 29
USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION
RATE = k [S2002-] [1-]"
* All CALCULATIONS MUST BE INCLUDED IN LAB REPORT
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