Moles S2082- 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 Aliquot Solution 1 Time (t in secs) Moles of S2082- Solution 2 Solution 3 Time (t in secs) Moles of S2082- Time (t in secs) Moles of S2082- 141 0.0002 74 0.0002 100 0.0002 2 341 0.0004 155 0.0004 204 0.0004 3 555 0.0006 235 0.0006 272 0.0006 4 796 0.0008 321 0.0008 366 0.0008 5 1010 0.001 414 0.001 472 0.001 6 1259 0.0012 504 0.0012 548 0.0012 7 1524 0.0014 590 0.0014 669 0.0014 Solution 1 Rates of Chemical Reactions 0 0 200 400 600 800 y = 1E-06x R² = 0.9964 1000 1200 1400 1600 1800 Time (Seconds) Moles S2082- Solution 2 Rates of Chemical Reactions Solution 3 Rates of Chemical Reactions 0.0016 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 0.0014 0.0012 y = 2E-06x R² = 0.9993 Moles S2082- 0.001 0.0008 0.0006 0.0004 y=2E-06x R² = 0.9993 0.0002 0 0 0 100 200 300 400 500 600 700 0 100 200 300 400 500 600 700 800 Time (Seconds) Time (Seconds) RESULTS AND DATA: 1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR EACH IF YOU KNOW HOW TO. MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS) 2. MAKE A BEST FUT LINE MOLES S2082. *MAKE A SCATTEPLOT - ADD TRENDLINE - ADD EQUATION OF LINE - SET INTERCEPT TO '0' TIME (SECONDS) CALCULATING THE RATE OF EACH SOLUTION: USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES st NOW CALCULATE THE RATE SLOPE 0-100L TUTAL VOLUME FOR EACH Sohutzon * REMEMBER RATE = A[1 st SOLUTION MAKE A DATA TABLE SIMILAR TO PAGE 80: [52002-] [1-] RATE (M/S) 1 0.05M 0.05 M 2 0.10 M 0.05M 3 0.0511 0.107 4 0.10 M 0.0257 NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y RATS =K [3400 *] [I¯]* [52082-] USE SOLUTIONS 2 AND 1 RATE 2 RATE [S₂002-], M (0·10H) x 0.050 M x = x [1] USE SOLUTIONS 3 AND I RATE 3 = [I]3 OR Q AND 4 RATE [] y = 29 USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION RATE = k [S2002-] [1-]" * All CALCULATIONS MUST BE INCLUDED IN LAB REPORT
Moles S2082- 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 Aliquot Solution 1 Time (t in secs) Moles of S2082- Solution 2 Solution 3 Time (t in secs) Moles of S2082- Time (t in secs) Moles of S2082- 141 0.0002 74 0.0002 100 0.0002 2 341 0.0004 155 0.0004 204 0.0004 3 555 0.0006 235 0.0006 272 0.0006 4 796 0.0008 321 0.0008 366 0.0008 5 1010 0.001 414 0.001 472 0.001 6 1259 0.0012 504 0.0012 548 0.0012 7 1524 0.0014 590 0.0014 669 0.0014 Solution 1 Rates of Chemical Reactions 0 0 200 400 600 800 y = 1E-06x R² = 0.9964 1000 1200 1400 1600 1800 Time (Seconds) Moles S2082- Solution 2 Rates of Chemical Reactions Solution 3 Rates of Chemical Reactions 0.0016 0.0016 0.0014 0.0012 0.001 0.0008 0.0006 0.0004 0.0002 0.0014 0.0012 y = 2E-06x R² = 0.9993 Moles S2082- 0.001 0.0008 0.0006 0.0004 y=2E-06x R² = 0.9993 0.0002 0 0 0 100 200 300 400 500 600 700 0 100 200 300 400 500 600 700 800 Time (Seconds) Time (Seconds) RESULTS AND DATA: 1. MAKE A GRAPH FOR EACH SOLUTION OR ONE FOR EACH IF YOU KNOW HOW TO. MOUES OF 52082- CONSUMED (Y-AXIS) US TIME IN SECONDS (X-AXIS) 2. MAKE A BEST FUT LINE MOLES S2082. *MAKE A SCATTEPLOT - ADD TRENDLINE - ADD EQUATION OF LINE - SET INTERCEPT TO '0' TIME (SECONDS) CALCULATING THE RATE OF EACH SOLUTION: USE THE SLOPE OF EACH LINE BECAUSE SLOPE = A MOLES st NOW CALCULATE THE RATE SLOPE 0-100L TUTAL VOLUME FOR EACH Sohutzon * REMEMBER RATE = A[1 st SOLUTION MAKE A DATA TABLE SIMILAR TO PAGE 80: [52002-] [1-] RATE (M/S) 1 0.05M 0.05 M 2 0.10 M 0.05M 3 0.0511 0.107 4 0.10 M 0.0257 NOW DETERMINE / CALCULATE THE ORDERS: XC AND Y RATS =K [3400 *] [I¯]* [52082-] USE SOLUTIONS 2 AND 1 RATE 2 RATE [S₂002-], M (0·10H) x 0.050 M x = x [1] USE SOLUTIONS 3 AND I RATE 3 = [I]3 OR Q AND 4 RATE [] y = 29 USE ABOVE CALCULATIONS TO SOLVE FOR K IN EACH SOLUTION RATE = k [S2002-] [1-]" * All CALCULATIONS MUST BE INCLUDED IN LAB REPORT
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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